Solve the equation. 50% X-30 = 52

Solve the equation. 50% X-30 = 52


50%x-30=52
0.5x=52+30
0.5x=82
x=82÷0.5
x=164



X + 52 = x-66 to solve the equation


From x + 52 to x-66
∵52≠66,
There is no solution to this problem



200 power of 2-201 power of 2?


200 power of 2-201 power of 2 = 200 power of 2 (1-2) = - 200 power of 2



Given the function f (x) = sin (π / 3-x), to get the image of its derivative f '(x), we only need to change the image of function f (x)————


The image of F '(x) = [sin (π / 3-x)]' * (π / 3-x) '= - cos (π / 3-x) = - sin [π / 2 - (π / 3-x)] = - sin (x - π / 6) f (x) = sin (π / 3-x) = - sin (x - π / 3) f (x) moves the image of y = SiNx to the right by π / 3 units, and the image of F' (x) is



9999 * 2222 + 3333 * 3334 = () how to operate easily?


9999*2222+3333*3334
=3333*(3*2222+3334)
=3333*(6666+3334)
=3333*10000
=33330000



8 () () () is not only the multiple of 2, but also the multiple of 3 and the multiple of 5


If the mantissa of a multiple of 2 must be one of 0,2,4,6,8,
If the mantissa of a multiple of 5 is only 5 or 0,
According to the above two, the mantissa of this number is 0
Now if the sum of all the numbers in a multiple of 3 must also be a multiple of 3, for example, 96 is a multiple of 3, then 9 + 6 = 15 must also be a multiple of 3
So the biggest number is 8970



The coefficient of numerator denominator is changed to integer x + Y / 4 / 3 / 4x-2y without changing the value of fraction
vjkdfhjdfhgjkdf


x+y/4+3/4x-2y



Take off the formula to calculate
4.15-3.75 × 10% - 8 / 5
1-39% × 1 / 2 △ 0.195
11 / 5 × 37% + 63 / 100 △ 5 / 11-2 / 5


1)=4.15-0.375-0.625
=4.15-1
=3.15
2)=1-0.195-0.195
=1-0.39
=0.61



If a is a rational number, the following statements are correct: A, a must be a positive number, B, 2A must be an even number, C, - a must be a negative number, D, a is either a fraction or an integer


The correct value is d
Because integers and fractions are called rational numbers



Given that x = 1 is the solution of the equation K (x-1) = 3x + 2K, find the algebraic value of 5K & sup2; - 2k-5


Because x = 1 is substituted by K (x-1) = 3x + 2K, then 0 = 3 + 2K, that is, k = - 1.5, and substituted by 5K & sup2; - 2k-5 = 9.25