9 8 7 6 5 4 3 2

9 8 7 6 5 4 3 2

9+8*7-6*5-4*3-2+1=22

2 3 4 5 6 8 9

How many do you want?
(1+2)+3+4+5-6-7+8-9 = 1
(1+2)+3+4-5+6+7-8-9 = 1
(1+2)+3+4*5-6*7+8+9 = 1
(1+2)+3-4-5-6-7+8+9 = 1
(1+2)+3*4*5/6*7-8*9 = 1
(1+2)-3+4-5-6+7-8+9 = 1
(1+2)-3-4+5+6-7-8+9 = 1
(1+2)-3-4+5-6+7+8-9 = 1
(1+2)-3*4*5/6+7-8+9 = 1
(1+2)-3/4-5-6*7/8+9 = 1
(1+2)*3-4*5+6+7+8-9 = 1
(1+2)*3*4+5*6+7-8*9 = 1
(1+2)*3*4+5*6-7*8-9 = 1
(1+2)*3*4-5+6*7-8*9 = 1
(1+2)*3*4-5-6-7-8-9 = 1
(1+2)*3/4-5-6*7/8+9 = 1
(1+2)/3*4-5-6+7-8+9 = 1
(1-2)+3+4-5+6-7-8+9 = 1
(1-2)+3+4-5-6+7+8-9 = 1
(1-2)+3-4+5+6-7+8-9 = 1
(1-2)+3*4*5/6-7+8-9 = 1
(1-2)+3/4+5+6*7/8-9 = 1
(1-2)-3+4+5+6+7-8-9 = 1
(1-2)-3-4+5-6-7+8+9 = 1
(1-2)-3-4-5+6+7-8+9 = 1
(1-2)-3-4*5+6*7-8-9 = 1
(1-2)-3*4*5/6*7+8*9 = 1
(1-2)*3+4*5-6+7-8-9 = 1
(1-2)*3*4-5-6+7+8+9 = 1
(1*2)+3-4*5+6-7+8+9 = 1
(1*2)+3*4+5+6-7-8-9 = 1
(1*2)-3+4*5+6-7-8-9 = 1
(1*2)-3-4+5*6-7-8-9 = 1
(1*2)-3*4-5+6-7+8+9 = 1
(1*2)-3*4*5+6*7+8+9 = 1
(1*2)-3*4*5-6+7*8+9 = 1
(1*2)-3*4*5-6-7+8*9 = 1
(1*2)*3+4+5-6-7+8-9 = 1
(1*2)*3+4-5+6+7-8-9 = 1
(1*2)*3+4*5-6*7+8+9 = 1
(1*2)*3-4-5-6-7+8+9 = 1
(1*2)*3*4-5+6-7-8-9 = 1
(1/2)-3/4+5+6*7/8-9 = 1
(1/2)*3*4-5+6-7-8+9 = 1
(1/2)*3*4-5-6+7+8-9 = 1
1+(2+3)+4+5-6-7+8-9 = 1
1+(2+3)+4-5+6+7-8-9 = 1
1+(2+3)+4*5-6*7+8+9 = 1
1+(2+3)-4-5-6-7+8+9 = 1
1+(2+3)*4+5-6*7+8+9 = 1
1+(2+3)*4-5*6-7+8+9 = 1
1+(2+3)*4/5+6+7-8-9 = 1

Second year physics unit conversion problem, speed + 10000, poke in! To be accurate!
2 times 10 to the fifth power micron = () cm () m? Note that it's a composite unit! Short answer,

1 000 000 micron (μ m) = 1 meter (m)
10 000 μ M = 1 cm
2 times 10 to the fifth power micron = (20) cm (0.2) M
Give a rose, hand has fragrance~
If it's still to be understood~

The second power of 4A + 12ab + the second power of 9b

4a^2+12ab+9b^2
=(2a+3b)^2

Resistor r1r2 is in series in the circuit, the voltage at both ends of R1 is 8V, the voltage at both ends of R2 is 4V, R1 + R2 = 60 ohm 1
2. Current in the circuit
3. Resistance of R1 and R2

The total voltage is VR1 + VR2 = 12V
The current in the circuit is I = 12V / (R1 + R2) = 12 / 60 = 0.2A
R1 = 8V / 0.2A = 40 ohm R2 = 4V / 0.2A = 20 ohm

A particle begins to move at a constant acceleration of 1m / s and 178; from its rest, then moves at a constant speed for 5 s, and then moves at a constant speed for 10 s to calculate its displacement

A particle begins to move at a constant acceleration of 1m / s and 178; from its rest, then moves at a constant speed for 5 s, and then moves at a constant speed for 10 s to calculate its displacement
Displacement = (1 / 2) × 1 × 5 & # 178; + (1 × 5) × 10
=25/2+50
=62.5m
I'm very glad to answer your questions. Skyhunter 002 will answer your questions
If you don't understand this question, you can ask,

We should not only master the complete square formula, but also understand the two variants of the complete square formula
A & # 178; + B & # 178; = (a + b) & # 178; - 2Ab and (a + b) & # 178; - (a-b) & # 178; = 4AB, please use these two variants to solve the following problems:
(1) Given a + B = 5, ab = 3, find the value of a & # 178; + B & # 178
(2) (a + b) &# 178; = 17, ab = 2, find the value of (a-b) &# 178
(3) Given that 1 / 4 of a + a = 4, find the value of 1 / 178 of a & # + A & #
(4) Given (a + b) &# 178; = 17, (a-b) &# 178; = 13, find the values of a & # 178; + B & # 178; and ab

1: A-b-178; + b-178; = (a + b) - 178; - 2Ab = 25-6 = 192. (a-b) - 178; = (a + b) - 178; - 4AB = 17-8 = 93. A + a = 1 / 4, a = 1 / 2, so a-178; + a-178; 1 / 2 = 2

One end of the light rod and light rope with length of L is fixed on the rotating shaft, and the other end is each tied with a small ball with mass of M. when the ball moves to the lowest point, the ratio of tension on the rod and rope is a.5:6 b.1:1 c.2:3 d.1:2

For the analysis of the rod, because it just makes a circular motion, the velocity at the highest point is 0. According to the kinetic energy theorem mg2l = MV ^ 2 / 2-0, the velocity at the lowest point can be obtained. Then, according to the fact that the pull reducing gravity is equal to the centripetal force f-mg = MV ^ 2 / L, the pull can be obtained
For the analysis of the rope, because it just makes a circular motion, at the highest point, Mg = MV ^ 2 / L, the highest point velocity can be obtained. According to the kinetic energy theorem, the lowest point velocity can be obtained. Similarly, the tensile force can be obtained
The final result is C

How many kilos is one ton equal to? How many jin is one ton equal to? How many kilos is one ton equal to? How many grams is one ton equal to?

One ton equals 1000 kg equals 2000 Jin equals 1000 kg equals 1000000 G

An object is weighed in air with a spring scale, and the reading is 0.8 n. if the object is completely immersed in water, the reading of the spring scale is 0.3 n. find out: (1) buoyancy of the object; (2) volume of the object; (3) density of the object. (G = 10N / kg)