What is 2x × (3x-5) × x equal to

What is 2x × (3x-5) × x equal to

2X×(3X－5）×X
=(6x²-10x) x X
=6x³-10x²
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Three fourths is eight fourths

Three out of four equals eight out of three
8 △ 3 / 4 = 32 / 3

What is four-thirds of eight?

=16
8^（4/3）=8*8(1/3)=8*2=16

There is a rectangular stadium. If its length and width are increased by 6 meters and the area is increased by 1236 square meters, how much is the perimeter of the original stadium

Let the length of the original rectangle be x meters and the width be y meters;
Area of rectangle = length × width
1236=（x+6）（y+6）-x*y
1236=xy+6x+6y+36-xy
6x+6y=1236-36
6x+6y=1200
6（x+y）=1200
x+y=1200/6=200
Perimeter of original rectangle = 2 (x + y) = 2 × 200 = 400 (m)

If AB = 8, satisfy a square b-ab's Square - A + B = 56, find a square + b square

a²b-ab²-a+b
=ab(a-b)-(a-b)
=(a-b)(ab-1)=56
=(a-b)(8-1)=56
a-b=8
therefore
a²+b²=(a-b)²+2ab=8²+16=64+16=80

Given that a is greater than 0, less than 1, and B is less than - 1, then the image of the function y = a ^ x + B does not pass through () a

Because when x > 0, y = a ^ x + B

Rearrange the following letters to form words
h o t s r ( ) l a l t ( ) l a l m s ( ) o g l n ( )

short tall small long

If the volume of a cylinder is 36 cubic decimeters more than that of a cone, the volume of a cylinder is______ Cubic decimeter, the volume of a cone is______ Cubic decimeter

The volume of cylinder: 36 △ 1-13, = 36 △ 23, = 54 (cubic decimeter), the volume of cone: 54-36 = 18 (cubic decimeter); answer: the volume of cylinder is 54 cubic decimeter, the volume of cone is 18 cubic decimeter

Use four operational symbols to connect the four numbers 1, 9, 9 and 7 into an equation (brackets are allowed), so that the result of the equation is equal to 79, then the equation is______ There may be many ways to write, only one is required

The answer is: (1 + 9) × 7 + 9 = 70 + 9 = 79

Let the probability density function of two-dimensional random variables (x, y) be f (x) = {K (3x & # 178; + XY) 0 ≤ x ≤ 1
Let the probability density function of two-dimensional random variable (x, y) be f (x) = {K (3x & # 178; + XY) 0 ≤ x ≤ 1, 1 ≤ y ≤ 3. Problem (1): determine the constant K (2): find P (x ≤ & # 189; y ≤ 2, find P (x ＜ & # 189; (4) find P (2x + y ≤ 3)

1) According to the total integral = 1 & nbsp; & nbsp; & nbsp; K ∫ (1 ~ 3) ∫ (0 ~ 1) (3x & # 178; + XY) DXDY = 1 & nbsp; & nbsp; & nbsp; & nbsp; ∫ (1 ~ 3) {(X & ∫ + X & ∫ 178; Y / 2) | (X: 1)} dy = 1 / K & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp