(2 / 3x + 7) / x = 6 / 5 calculation

(2 / 3x + 7) / x = 6 / 5 calculation

(2/3x+7)/x=6/5
6x=5(2/3x+7)
6x=10/3x+35
x=105/8

4 X-2 = 1-6 4-3x x =?

X = - 10 / 3, if I understand your question correctly

6 x-4-4 3x-2 = 1

(x-4)/6-(3x-2)/4=1
4(x-4)-6(3x-2)=24
4x-16-18x+12=24
-14x-4=24
-14x=28
x=-2
If you don't understand, I wish you a happy study!

3/2x+1-6/5x-1=1

3/2x+1-6/5x-1=1
(3/2x-6/5x)=1-1+1
3/10x=1
x=3/1/3

If M = {0, 1, 2}, n = {(x, y) | x-2y + 1 ≥ 0 and x-2y-1 ≤ 0, x, y ∈ m}, then the number of elements in n is______ ．

Draw the feasible region represented by the set n = {(x, y) | x-2y + 1 ≥ 0 and x-2y-1 ≤ 0, x, y ∈ m}, as shown in the figure. From the meaning of the question, we can see that there are only four points (0,0), (1,0), (1,1) and (2,1) in n that satisfy the condition, so the answer is: 4

It is easy to calculate (11 / 12 × 19) × (5 / 6 × 38)
(11 / 12 × 19) × (5 / 6 × 38)
Delivery, etc

=(11 / 12 × 6) × (5 / 19 × 38)
=11 / 2 × 5 / 2
=55 out of 4

The line y = KX + 3 and the circle (x-3) ^ 2 + (Y-2) ^ 2 = 4 intersect at two points Mn, | Mn | > = 2 "3. Find the range of K

Let d be the distance from the center of the circle to the straight line y = KX + 3, so D & # 178; + (Mn / 2) &# 178; = R & # 178; that is, D & # 178; = 4 - (Mn / 2) &# 178; because Mn / 2 ＞ 3, so (Mn / 2) &# 178; ≥ 3, so - (Mn / 2) &# 178; ≤ - 3, so 4 - (Mn / 2) &# 178; ≤ 1, that is

4 of 19 times 16 of 13 minus 2 of 13 times 6 of 19
Simple calculation

4 / 19 × 16 / 13-2 / 13 × 6 / 19 2 / 13 divided by 2 / 3 6 / 19 multiplied by 2 / 3
=4/19×16/13-3/13×4/19
=4/19×(16/13-3/13)
=4/19×13/13
=4/19×1
=4/19

The form of the square of 2x + 4x-1 = 0 into the square of (x + m) = k is

2x²+4x=1
x²+2x=1/2
x²+2x+1=1/2+1
(x+1)²=3/2

Writing ratio [1] 6:9 And 9:12 [2] 1:6 And 6:5

6: 9 and 9:12 are not proportional
1:5: 1:6 = 6:5