Calculation: (1,4 / 5) - 5 / 6 + 7 / 10-8 / 15) times (- 30) To process! To be 100% right!

Calculation: (1,4 / 5) - 5 / 6 + 7 / 10-8 / 15) times (- 30) To process! To be 100% right!

（9/5-5/6+7/10-8/15）*（-30）
=（54/30-25/30+21/30-16/30）*（-30）
=34/30*（-30）
=-34
The calculation of the problem first to divide, that is to find the minimum common divisor is 30, and then calculate to solve it
I hope my answer can help you@

4X + 6 × (8-x) = 38 (solving equation)

[answer] x = 5
[analysis] 4x + 48-6x = 38
-2x+48=38
-2x=-10
x=5
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2x=(5x-24)*7／16 2/5x=(x-24)*7/16
(3x-24)/2x=9/7

2x=(5x-24)*7／16
2x=35/16x-21/2
3/32x=21/2
x=7/16
2/5x=(x-24)*7/16
2/5x=7/16x-21/2
32/80x=35//80x-21/2
3/80x=21/2
x=7/40
(3x-24)/2x=9/7
3x-24=18/7x
3/7x=24
x=56

Given the function f (x) = - x2-2x, G (x) = x + 14x, X ＞ 0x + 1, X ≤ 0, if there are four real roots of the equation G [f (x)] - a = 0, then the value range of a is______ ．

The function y = g [f (x)] has four intersections with the function y = a, as shown in the figure: 1 ≤ a < 54 can be obtained by combining with the image, so the answer is [1,54]

How to write English words of calculator

calculator

What does the formula r = (r1r2) / (R1 + R2) mean in electricity?
For example: the electrical Formula 1 / r = 1 / R1 + 1 / r2 + 1 / R3 is that the reciprocal of the total resistance in the parallel circuit is equal to the sum of the reciprocal of the branch resistance

The reciprocal of the total resistance in parallel circuit is equal to the sum of the reciprocal of the branch resistance
It is obtained by I / r = 1 / R1 + 1 / r2 deformation

Find the sum of the coefficients in the expansion of (2x-1) ^ 5 and the sum of the binomial coefficients

Let x = 1 be substituted into the sum of the coefficients = 1

Given a + B = 2, ab = 3 / 4, find the value of a ^ 2B + 2A ^ 2B ^ 2 + AB ^ 3
Thank you!

Solution
A & # 179; B + 2A & # 178; B & # 178; + AB & # 179; - this one
=ab(a²+2ab+b²)
=ab(a+b)²
=3/4×2²
=3/4×4
=3

Turn the following equation into the general formula of quadratic equation of one variable, and then write out his quadratic coefficient, primary coefficient and constant term
-3X²+1＝4x
2x﹙x-1﹚=3X²-X
-3X＋4X²=0
(M + 1) x & # 178; + M-1 = 4x (x unknown, m ≠ - 1)

-3X²+1＝4x
3x²+4x-1=0
Coefficient of quadratic term 3, coefficient of primary term 4, constant term-1
2x﹙x-1﹚=3X²-X
x²+x=0
Coefficient of quadratic term 1 coefficient of primary term 1 constant term 0
-3X＋4X²=0
4X²-3X=0
Coefficient of quadratic term 4 coefficient of primary term - 3 constant term 0
(M + 1) x & # 178; + M-1 = 4x (x unknown, m ≠ - 1)
﹙m＋1﹚X²-4x＋m-1=0
Coefficient of quadratic term m + 1 coefficient of primary term-4 constant term M-1

Solve the equation, x ^ 2-6x-16 = 0, help,
x^2-6x-16=0

x^2-6x-16=0
(x+2)(x-8)=0
X + 2 = 0 or X-8 = 0
therefore
x1= -2
x2=8