How to solve (x + 60) = 2:3 Wrong, X: (x + 60) = 2:3

How to solve (x + 60) = 2:3 Wrong, X: (x + 60) = 2:3

It is reduced to 2 (x + 60) = 3x and then transferred to x = 120

If x = 4 is the solution of the equation x2-a = 4, then a is equal to ()
A. 0B. 12C. -3D. -2

According to the meaning of the question, 42-a = 4, a = - 2

How to solve the equation x-16 = 60% + 4

X-16=4.6
X=20.6

(x ^ 4-y ^ 4) / (x ^ 2 + y ^ 2) monomial divided by monomial

(x^4-y^4)=(x^2-y^2)(x^2+y^2)
So (x ^ 4-y ^ 4) / (x ^ 2 + y ^ 2) = (x ^ 2-y ^ 2) (x ^ 2 + y ^ 2) / (x ^ 2 + y ^ 2) = (x ^ 2 + y ^ 2)

Given YX ^ 2 + 2XY ^ 3 + 3 = - 18, find dy / DX

The two sides are derived from X
y'x^2+2xy+2y^3+4xy^2y'=0
Just solve y '

Conversion of water density units
What is the density of cubic water in metric tons per millimeter?
The unit I want is: metric ton / millimeter to the third power
I see the unit.
Unit to convert it
Also, I want metric tons, not tons!

First of all, let me say tons and metric tons. In our country, tons and metric tons are 1000 kg
In Britain and the United States, the ton is 1016 kg, and the metric ton is 1000 kg
Generally, the density of water is 1000 kg / m3
One cubic meter is equal to the ninth millimeter of 10
So one ton per cubic meter is equal to minus 9 tons per cubic millimeter
This is actually very simple. One meter is equal to the third millimeter of ten
One cubic meter is naturally equal to the 9th power millimeter. For those above, don't look at such a simple thing. You have to calculate it carefully
One ton per cubic meter is equal to minus 9 tons per cubic millimeter
The answer, again
How many times will you understand it?
Metric tons and tons are one thing in our country
It's different only abroad

Simple calculation of 99 × 1 / 4 × 100 × 3 / 4
If you're right, what should I do

99×1/4×100×3/4
=99/4×300/4
=297/16

The two points a and B on the parabola y ^ 2 = 4x are in the first and fourth quadrants respectively, f is the focus, and | AF | = 2, | BF | = 5. The equation of the straight line AB is solved

Let a (x1, Y1), (X2, Y2) the distance from the point on the parabola to the focus = the distance to the collimator | | AF | = 2 = X1 + 1x1 = 1 | BF | = 5 = x2 + 1x2 = 4 ∵ a, B in the first and fourth quadrants 4x1 = Y1 ^ 2y1 = 24x2 = Y2 ^ 2Y2 = - 4a (1,2) B (4, - 4) let aby = KX + B2 = K + B-4 = 4K + B, respectively

The volume of a cuboid is equal to that of a cylinder. If the area of the bottom of the cuboid is 2 / 5 of the area of the bottom of the cylinder, then the height of the cuboid is the height of the cylinder?

V length = long bottom * long height = = column bottom * column height = V column
Long bottom / column bottom = column height / long height
1/(2/5)=2.5

Simple calculation of 3.54 times 99 + 3.54

Digong factor
=3.54×(1+99)
=3.54×100
=354