The reciprocal of 3 / 4 is 1 and 1 / 3, right?

The reciprocal of 3 / 4 is 1 and 1 / 3, right?

The reciprocal is four-thirds = one and one-third
The answer is right!

1. If a and B are reciprocal to each other, then 15 parts of a × 3 parts of B = (), 3 parts of B × 4 parts of a = ()
1. If a and B are reciprocal to each other, then 15 parts of a × 3 parts of B = (), 3 parts of B × 4 parts of a = ()
2. If a × 3 / 4 = B × 3 / 5 = C × 7 / 3, and a, B and C are not zero, the three numbers a, B and C are arranged in descending order
3. The difference between the reciprocal of two consecutive natural numbers is 1 / 12, which are () and (), respectively
4. The difference between two consecutive odd numbers is 2 / 143, and the reciprocal of the two consecutive odd numbers are () and (), respectively
If I can do it, I will offer a reward

1. If a and B are reciprocal, then 15 / a × 3 / b = (1 / 45), B / 3 × A / 4 = (12)
2. If a × 3 / 4 = B × 3 / 5 = C × 7 / 3, and a, B, C are not 0, the order of a, B, C from large to small is C > b > a
3. The difference between the reciprocal of two consecutive natural numbers is 1 / 12, which are (3) and (4) respectively
4. The difference between two consecutive odd numbers is 2 / 143, and the reciprocal of the two consecutive odd numbers are (1 / 11) and (1 / 13) respectively

What is the reciprocal of 4 and 1 / 3 sum

4 and 1 / 3 equals 13 / 3, so the reciprocal of 4 and 1 / 3 sum is 3 / 13!

Five cards 12345 in a row which out of one or two swap position how to become 54321
Like poker
1 2 3 4 5
Ask to take one or two of them in the same position, 2 for example, 3 and 4 change to 1, the middle will become 13425, or one for example, 5 change to 3, the back will become 12354, ask to change three times
How about 54321

：12345-----34125-----32541-----54321
Your understanding!:)

Inequality | (x + 3) / X | > (x + 3) / x, inequality (X & # 178; - 9) / (X-2) > 0

1. Solve the inequality | (x + 3) / X | > (x + 3) / X
When (x + 3) / X

Ask a math problem, there should be a calculation process, thank you!
Put the natural number 1,2,3,4 Arrange them as shown in the figure below
1 2 5 10
4 3 6 11
9 8 7 12
16 15 14 13
Ask: the sixth number in the leftmost column from top to bottom is (), and the 25th number is ()
From left to right, the sixth number in the top row is (), and the 25th number is ()

Leftmost number = the square of the number of rows
The sixth number in the leftmost column from top to bottom is (36), and the 25th number is (625)
Top number = (column number - 1) square + 1
From left to right, the sixth number in the top row is (26), and the 25th number is (577)

What is the distance formula between two straight lines in space

These two lines must be parallel, so let them be in the rectangular coordinate system (X-Y)
Y = KX + A and y = KX + B
Then d = |a-b | / [(1 + K ^ 2) ^ (1 / 2)]
(the denominator is 1 plus K under the root)

Let a and B satisfy 2A + B = 9. (I) if | 9-b | + | a | < 3, find the value range of X; (II) if a and b > 0, and z = A2B, find the maximum value of Z

(i) So | 9-b | + | a | < 3 can be changed into 3 | a | < 3, that is | a | < 1, and the solution is - 1 | < 1. So the value range of a is - 1 | < 1. (II) because a, b > 0, 2A + B = 9, so z = A2B = a · a · B ≤ (a + A + B3) 3 = (2a + B3) 3 = 33 = 27, if and only if a = B

Y = e ^ x * (SiNx cosx) for dy?
E ^ x means the x power of E

dy=[e^x*(sinx-cosx)+e^x*(cosx+sinx)]dx
=2e^x*sinxdx

Let a, B and C be unit vectors and a · B = 0, then the minimum value of (A-C) · (B-C) is ()
A.-2
B.（√2）-2
C.-1
D.1-√2

The original formula is c * C - (a + b) * C
Where c * C = 1, then the original formula needs to take the minimum value, (a + b) C needs to take the maximum value, (a + b) is a vector whose size is root 2, C is a vector whose size is 1, when the angle between (a + b) and C is 0, the value of (a + b) C is the maximum, that is root 2, the original formula has the minimum value of 1-root 2