Solution equation and proportion: X3 = 3.7515 & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; 23: x = 910:0.6 & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; X (1-15%) = 34

Solution equation and proportion: X3 = 3.7515 & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; 23: x = 910:0.6 & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; X (1-15%) = 34

（1）x3=3.7515          15x=3×3.75   15x÷15=11.25÷15         x=0.75；（2）23：x=910：0.6      910x=23×0.6  910x÷910=25÷910        x=49；（3）x（1-15%）=34           85%x=34     85%x÷85%=34÷85%             x=40．

(1.2 + x) times 9 = 15.3 to solve the equation

（1.2+X）×9=15.3
1.2+X=1.7
X=1.7-1.2
X=0.5

We know that | m-2 | + (3-3n) ^ 2 = 0, and simplify 2x ^ (m-n + 1) y3-6y (m-n) x ^ 2

|M-2 | + (3-3n) ^ 2 = 0, simplify 2x ^ (m-n + 1) y3-6y (m-n) x ^ 2
The absolute value of the sum of squares is always non negative, so the sum is zero only when both are zero
So m-2 = 0, 3-3n = 0
=> m=2,n=1
So M-N + 1 = 2
m-n=1
2x^(m-n+1)y3-6y(m-n)x^2
=2x^2y^3-6y^2x^2

A car runs two fifths of the whole journey in three fourths of an hour, 90 kilometers. How many kilometers is the whole journey? How many parts of the whole journey in four hours?

90 △ 2 / 5 = 225 km
2/5÷3/4×4=32/15

Find a natural number within 700 so that the natural number is the cubic sum of three different odd numbers and a multiple of 11
Who can help me to have a look

495
If the cube of a natural number does not exceed 700, then the natural number is less than 9,
And if it's odd, it can only be 1, 3, 5, 7
Their cubes are 1, 27, 125 and 343 respectively. If you try four combinations, you can see that the number is 495, which is the cubic sum of 3, 5 and 7 and a multiple of 11

The sun, the universe, the Milky way, the moon and the earth are in a certain order

Universe Galaxy sun Earth Moon (from big to small)

X times * (half minus three eighths) = three tenths. How can we solve this equation

X times * (half minus three eighths) = three tenths
X times * one eighth = three tenths
X = three tenths ／ one eighth
X = two and two fifths

As for the relationship between elastic force and friction force, the following statement is correct ()
A. If there is elasticity between two objects, there must be friction. B. if there is friction between two objects, there must be elasticity. C. the direction of elasticity and friction must be perpendicular to each other. D. when the elasticity between two objects disappears, friction can still exist for a period of time

A. It can be seen that if there is friction, there must be elasticity; if there is elasticity, there may not be friction. So a is wrong, B is correct

If the solution of the equation (1-A) x = 1-2x about X is negative, then the value range of a is______ ．

Solve the equation: x = 13 − a, ∵ solution is negative, ∵ 13 − a < 0, solution: a > 3

The car and the train run from both sides of a and B at the same time. When they meet, the car runs 2 / 5 of the whole journey. If the car runs 60 kilometers less than the truck, the total number of trucks will increase
How many kilometers did you travel?

60 divided by 1 / 5 = 300km
300 times 3 / 5 = 180km