5(x-2)-2(x-1)>3 The solution set is expressed on the number axis

5(x-2)-2(x-1)>3 The solution set is expressed on the number axis

5(x-2)-2(x-1)>3
5x-10-2x+2>3
3x-8>3
3x>11
x>11/3
If you don't understand, I wish you a happy study!

How to do these simple operations of fraction multiplication in Grade 6? 1.55 times 65:17 2.99 times 100:21 3.34 times 33:32 4.101 times 1000:999

2、99=（100-1） 3、34=（33+1） 4、1001=（1000+1）
Adopt

A special solution of the differential equation y '' '+ y' = SiNx should be formal

The characteristic equation of homogeneous equation is: R ^ 3 + r = 0, the characteristic root is 0, ± I
For SiNx, I is the single root of the characteristic equation
So the special solution y * = x (acosx + bsinx)

It is known that the solution set of inequality (M2-4) x2 + (M + 2) X-1 < 0 about X is r, and the value range of real number m is obtained

(1) When m ^ 2-4 = 0, then M = ± 2, when m = 2, the solution set of inequality is not empty, so it is discarded; when m = - 2, the solution set of inequality is empty, so when m = - 2, the condition is satisfied
(2) When m ^ 2-4 ≠ 0 (i.e. m ≠ ± 2), the,
Δ =（m+2)^2-4（m^2-4)(-1)

1.2/0.36 vertical calculation

3.3333333333…… loop

LIM (x tends to 0) (√ (x ^ 2 + 1) - 1) / x,
lim(x->0) (√(x^2+1)-1)/x

Multiplication √ (X & # 178; + 1) + 1
The molecule is the square difference, = x & # 178;
So the original formula = limx & # 178 / / x [√ (X & # 178; + 1) + 1]
=limx/[√(x²+1)+1]
=0

Bivariate linear equation, 2x-3y = - 1, 4x-y = 5
2x-3y=-1
4x-y=5
2x+y=4
x+2y=5
3(x-1)=4(y-4)
5(y-1)=3(x+5)
The following is solved in two ways: one is the substitution method, and the other is the method of sorting out the formula,
x+y/3+x-y/2=6
3(x+y)-2(x-y)=28

2x-3y=-1①
4x-y=5 ②
② X3, the result is: 12x-3y = 15 ③
③ - 1, the result is: 10x = 16
x=1.6
Substituting x = 1.6 into 2 gives y = 1.4

Sequence 5,20,51,104,)
What should (?) be and what rules?
5 10 17 26 37 what are the rules to follow?

It should be: 185
5=1*5
20=2*10
51=3*17
104=4*26
Should be = 5 * 37

Let the derivative of function f (x) not exist at x = x0, then the limit of curve y = f (x) does not exist at x = x0?

Not necessarily
e.g
f(x) =|x|
f'(0+) = 1,f'(0-) =-1
=> f'(0) does not exist
but
lim(x->0)f(x) = 0

How to estimate the volume of your body and calculate the volume expression

Fill a large container with water and put it in a larger container
The whole body is immersed in water, and the water discharged will be in a larger container
Measure the volume of discharged water = human volume