Is f (x) = - x ^ 3 + 1 an increasing function or a decreasing function on (- ∞, 0)? Process (use the formula A ^ 2-B ^ 2 = (a-b) (a ^ 2 + AB + B ^ 2))

Is f (x) = - x ^ 3 + 1 an increasing function or a decreasing function on (- ∞, 0)? Process (use the formula A ^ 2-B ^ 2 = (a-b) (a ^ 2 + AB + B ^ 2))

Let X10 be: F (x1) > F (x2)
Ψ f (x) is a decreasing function on (- ∞, 0)

How to find the monotone interval (increasing interval, decreasing interval) of F (x) = asin (ω x + φ), detailed inequality formula can be applied to high school mathematics problems
Hope to get a detailed explanation, if good, add points

First consider SiNx, which is a function with a period of 2 π
Its increasing interval is [2K π - 0.5 π, 2K π + 0.5 π]
The subtraction interval is [2K π + 0.5 π, 2K π + 1.5 π]
For f (x) = asin (ω x + φ)
A>0
(1) Increasing interval
2kπ-0.5π≤ωx+φ≤2kπ+0.5π
(2kπ-0.5π-φ)/ω≤x≤(2kπ+0.5π-φ)/ω
(2) Minus interval
2kπ+0.5π≤ωx+φ≤2kπ+1.5π
(2kπ+0.5π-φ)/ω≤x≤(2kπ+1.5π-φ)/ω
Here K is an arbitrary integer
A 0 is the opposite
(1) Minus interval
2kπ-0.5π≤ωx+φ≤2kπ+0.5π
(2kπ-0.5π-φ)/ω≤x≤(2kπ+0.5π-φ)/ω
(2) Increasing interval
2kπ+0.5π≤ωx+φ≤2kπ+1.5π
(2kπ+0.5π-φ)/ω≤x≤(2kπ+1.5π-φ)/ω
A = 0 is always 0, no matter increase or decrease
Thank you for your reminding
Another typo has been fixed

What are the words in the couplet

Connect, connect, link, link, link, link, link, link, link, link, link, link, link, link, link, link, link, link
rolling
continuously
continuous
as closely linked as flesh and blood
Good things happen all the time

The volume of a cone is 12 cm3 less than that of a cylinder with the same base and height. The volume of this cone is______ What is the volume of a cylinder______ ．

Let the volume of cone be x, the volume of cylinder be 3x, 3x-x = 12 & nbsp; & nbsp; 2x = 12 & nbsp; & nbsp; X = 63 × 6 = 18 (cubic centimeter), answer: the volume of cylinder is 18 cubic centimeter, the volume of cone is 6 cubic centimeter. So the answer is: 6 cubic centimeter, 18 cubic centimeter

Use seven sixes to make up four numbers, plus the operation symbol is equal to 600. How to calculate? Guilty answer
Come on

Let these six numbers be 6,6,66 and 666 respectively,
Then 666 + 6-66-6 = 600

Given that a is an integer, X and y are the integer solutions of the equation x & # 178; - XY ax + ay + 1 = 0, the value of X-Y can be obtained

x(x-y)-a(x-y)+1=0
(x-y)(x-a)=-1
So if X-Y and x-a are all - 1, they can only have
X-Y = 1 or - 1

Given that Y-1 is positively proportional to x square + 2 and y = 0 when x = 2, write the functional expression of Y and X

Y-1=k(x^2+2)
When x = 2, y = 0, - 1 = 6K, k = - 1 / 6
-->Y-1==-1/6(x^2+2)
Don't be lazy about such a basic topic

ABCD*9=DCBA
Find the values of a, B, C and D
(* is a multiple sign)

ABCD × 9 DCBA because DCBA is still four digits, a must be 1, otherwise ABCD × 9 will not be four digits, and because D × 9's single digit is 1, d must be 9. Write the formula as 1 bc9 × 9 9CB 1, because B × 9 has no carry (otherwise a × 9 + carry product is not four digits), so B must be 0 (because a = 1) and because C

The location of the first-order function y = x + m and the inverse scale function y = m / X is shown in the figure. Now put the right triangle ABC with an area of 3 on the position shown in the figure, where the point a and the intersection of the image of the second-order function coincide in the first quadrant, the point C is at the origin, and the BC side is on the X axis. (1) can you completely determine the relationship between the first-order function and the inverse scale function? If you can, please write out the relationship, Please explain the reason. (2) if the intersection point of the image of the line and the inverse scale function in the third quadrant is D, do you know the relationship between the area of △ ode and △ oba? Why

(1) Let a (a, b) bring in y = m / X to get b = m / a 〈 AB = m ∵ s △ ABC = 1 / 2Ab * ob = 1 / 2Ab = 3 〉 AB = 6 〉 M = 6 / x y = x + 6 (2) s △ ode = s △ oba reason: let D (C, d) bring in y = 6 / X to get d = 6 / C 〉 CD = 6 ∵ de ⊥ X axis 〉 s △ ode = 1 / 2CD = 3 = s △ ABC, that is s △ ode = s △ ob

Two cylinders with the same bottom area, one is 4.81 cubic decimeters high, the other is 3 decimeters high. What's the volume?

If you know the height and volume of a cylinder, first calculate its bottom area: divide the volume by the height is the bottom area, 81 / 4.5 = 18 (square decimeter)
Because their bottom areas are the same, we can multiply the calculated bottom area by the known height: 18 * 3 = 54 (cubic decimeter)