109 degrees, 11 minutes, 4 seconds divided by 7!

109 degrees, 11 minutes, 4 seconds divided by 7!

109°11‘4’’÷7
=15°251‘4’‘
=15°35’364‘’
=15°35‘52’‘
Method analysis: divide the last digit by 7, multiply the remainder by base 60 and add to the next digit
Hope to adopt, if you don't understand, please ask

Find the limit of function, f (x) = (√ x ^ 2 + x) - (√ x ^ 2 + 1). When x tends to positive infinity, find the limit of F (x) (to solve the problem process)

F (x) = √ (x ^ 2 + x) - √ (x ^ 2 + 1) = [√ (x ^ 2 + x) - √ (x ^ 2 + 1)] * [√ (x ^ 2 + x) + √ (x ^ 2 + 1)] / [√ (x ^ 2 + x) + √ (x ^ 2 + 1)] = (x-1) / [√ (x ^ 2 + x) + √ (x ^ 2 + 1)] = (1-1 / x) / [√ (1 + 1 / x) + √ (1 + 1 / x ^ 2)]. Therefore, when x →∞, 1 / X → 0, then

Simple calculation of 20 × 7 / 21 + 20 × 21 / 7
This is a simple problem

20/21×3/7 +20/7×11/21
=20/7×3/21+20/7×11/21
=20/7×(3/21+11/21)
=20/7×2/3
=40/21

Ask some calculation questions and factorization
Calculate 3,
1.2[X(X+2)(X+1)-3]+(x-1)(x-2)-3X(X+3)
2.(2X-3Y+1)(2X+3Y+1)
3.(X-2Y+3Z)^2
Factorization, just ask if the following formula can be decomposed? If it can be decomposed,
1.A^2+B^2(B-A)
2.(3B+2A)(3B-2A)
3.[(A+C)^2*B^2]^2
Please help me / sorry, I only have 14 points / 555

1,2[X(X+2)(X+1)-3]+(x-1)(x-2)-3X(X+3)
=2(X^3+3X^2+2X-3)+X^2-3X+2-3X^2-9X
=2X^3+4X^2-8X-4
2,(2X-3Y+1)(2X+3Y+1)
=(2X-3Y)(2X+3Y)+4X+1
=4X^2-9Y^2+4X+1
3,(X-2Y+3Z)^2
=X^2+4Y^2+9Z^2-4XY+6XZ-12YZ
Now, let's do the following three things!
1. A ^ 2 + B ^ 2 (B-A), if it's factorization, then it's complete! If you mean solving equations and so on! I can tell you! This is not complete!
2. (3b + 2a) (3b-2a), complete!
3. [(a + C) ^ 2 * B ^ 2] ^ 2 is complete! But (a + C) ^ 4 * B ^ 4 may look better!

Simple calculation of 240 divided by (104-89)

240÷（104-89）=240÷15=16

If the line L passes through the point m (1,5) and the inclination angle is 2 beats / 3, then the parameter equation of the line is

Solution
sin2π/3=√3/2
cos2π/3=-1/2
The parametric equation
x=1-t/2
y=5+√3t/2

3.25 × 7,. 8-7.8 (simple calculation) (5x-4) △ 5 = 4 (solving equation) 5x-3x1.3 = 0 (solving equation) (x + 0.5) × 3 = 45 (solving equation)

3.25×7,.8-7.8
=（3.25-1）×7.8
=17.55
（5x-4）÷5=4
5x-4=20
5x=24
x=4.8
5x-3x1.3=0
5x=3.9
x=0.78
（x+0.5)×3=45
x+0.5=15
x=14.5

If M = {0, 1, 2}, n = {(x, y) | x-2y + 1 ≥ 0 and x-2y-1 ≤ 0, x, y ∈ m}, then the number of elements in n is______ ．

Draw the feasible region represented by the set n = {(x, y) | x-2y + 1 ≥ 0 and x-2y-1 ≤ 0, x, y ∈ m}, as shown in the figure. From the meaning of the question, we can see that there are only four points (0,0), (1,0), (1,1) and (2,1) in n that satisfy the condition, so the answer is: 4

1/11-11/31+2/11-12/31+3/11-13/31+.+10/11-20/31=

You add all the denominators of 11, add all the denominators of 31, and subtract the two. The answer is 5-5 = 0
(1+10)*10/2 / 11 - ((11+20)*10/2) / 31 = 55 / 11 - 155 / 31 = 0

If two points m and N on the number axis represent numbers m and N respectively, then the distance between two points m and N can be expressed as: Mn=

|m-n|