Four numbers, 1 / 3, 1 / 6 and 1 / 10, are added with appropriate operation symbols to form the formula 1. Maximize the result 2. Minimize the result——————————

Four numbers, 1 / 3, 1 / 6 and 1 / 10, are added with appropriate operation symbols to form the formula 1. Maximize the result 2. Minimize the result——————————

1 the maximum result is 1 / 3 (1 / 5 * 1 / 6 * 1 / 10) = 100
The minimum result is 1 / 3 * 1 / 5 * 1 / 6 * 1 / 10 = 1 / 900

Use 1 / 3, 1 / 5, 1 / 6, and 3 / 4 tenths to form the formula
The largest number of
The minimum number of
The result is one
Write two formulas that make the number equal to the other numbers
OK, add

The largest number: 1 / 3 ／ 1 / 5 ／ 1 / 6 ／ 3 / 10 = 100 / 3
The minimum number: 1 / 3 × 5 / 1 × 6 / 1 × 10 / 3 = 1 / 300
The number is 1:3 of 1 + 5 of 1 + 6 of 1 + 10 of 3 = 1
The number obtained is equal to other numbers: 1 / 3-5 / 1-6 / 1 + 3 / 10 = 0
1 / 3 + 1 / 5-1 / 6 + 3 / 10 = 2 / 3

How to solve equations in primary school mathematics published by people's Education Press
1. The distance between city a and city B is 560 kilometers. The two trains leave from city a and city B at the same time. They meet 3.5 hours later. Car a travels 85 kilometers per hour, and how many kilometers does car B travel per hour?
2. Use a 54 cm long iron wire to form a rectangle, so that the length is twice the width. What is the length and width of the rectangle? What is the area?
Another question: a two-tier bookshelf has 360 books. The number of books on the upper shelf is three times that of the lower shelf. How many books are there on the upper shelf and the lower shelf?
Some data of an invoice can't be seen clearly. Can you work out the original data?
Quantity of goods unit price amount
60 chairs 22
Total amount: RMB four thousand and twenty
On behalf of the unknowns, who knows how to write it, please tell me. I've just thought about it. There must be the unknowns X

1. The distance between city a and city B is 560 km. Two trains leave from city a and city B at the same time. They meet after 3.5 hours. Car a travels 85 km per hour, and car B how many km per hour? If car B travels x km per hour, we can get (85 + x) × 3.5 = 560, 85 + x = 560 △ 3.585 + x = 160x = 75

Let y = f (x) be a monotone function on R, then the sum of the two roots of the equation f (x ÷ (x-1)) = f (x + 1) is

f(x÷(x-1))=f(x+1)
It's a monotone function
So x / (x-1) = x + 1
x=(x+1)(x-1)
x²-x-1=0
So the sum is X1 + x2 = 1

What are the M +, MS, Mr and MC on the calculator

M +: put the currently displayed value in the memory and interrupt the digital input. (memory +) m -: subtract the currently displayed value from the memory and interrupt the digital input. (memory -) MR: call the memory content. (memory recall) ms: store the displayed content in the memory. (memory save) MC: clear the memory

Why is resistance R = r1r2 / R1 + R2 in parallel circuit given a detailed answer

　　1/R=1/R1+1/R2=R1+R2 / R1R2 R=R1R2/R1+R2
I hope my answer is that you are satisfied,

The difference between the coefficients of binomial expansion and binomial expansion

The binomial coefficient is different from that of the term. The binomial coefficient is C, choose which one;
The coefficient of the term has to be calculated, so there is no constant of X
Please refer to the textbook for details

It is stipulated that an operation #, satisfying a # - B = AB + A-B, for example: 2 # - 3 = 2 * 3 + 2-3 = 5, find (- 4) # - 5) # - 6

a#b=ab+a-b,（-4）#（-5）#（-6)=[（-4）*（-5）+（-4）-（-5）]#(-6)=
21#(-6)=21*(-6)+21-(-6)=-99

If the equation (m ^ 2-4) x ^ m + 3x-2 = 0 is a quadratic equation of one variable about X, find the value of M and write the coefficient of the equation
If the equation (m ^ 2-4) x ^ m + 3x-2 = 0 is a quadratic equation of one variable about X, find the value of M and write out the coefficient of quadratic term of the equation

If the equation (M & # 178; - 4) x ^ m + 3x-2 = 0 is a quadratic equation of one variable with respect to x, find the value of M and write out the quadratic coefficient of the equation
From (M & # 178; - 4) x ^ m + 3x-2 = 0, we know that x ≠ 0; therefore, when m = - 1, the original equation becomes - (3 / x) + 3x-2 = (- 3 + 3x & # 178; - 2x) / x = 0,
Since x ≠ 0, we can get the same solution equation 3x & # 178; - 2x-3 = 0 by multiplying X by both sides of the equation, so m = - 1 and the coefficient of quadratic term is 3

The solution equation is: 2x + 5 power of 3 - 2x + 2 power of 3 = 2106

3^(2x+5)-3^(2x+2)=2106
3^(2x+2)×3³-3^(2x+2)=2106
3^(2x+2)×(3³-1)=2106
3^(2x+2)×26=2106
3^(2x+2)=2106/26=81
3^(2x+2)=81=3⁴
2x+2=4
2x=2
x=1