A = 8, the value of expression a > > 2 is?

A = 8, the value of expression a > > 2 is?


Move two digits to the right without sign. It turns out to be 1000, then 0010. The answer is 2



Int a = 2, B = 6, C = 8;, the value of expressions (a, b), (C, 10), the program
10. Let int a = 2, B = 6, C = 8;, the values of expressions (a, b), (C, 10) are ()
A.2 B.6
C.8 D.10
This is my answer,
#include "stdio.h"
void main()
{
int a=2,b=6,c=8,d;
d=(a,b),(c,10);
printf("%d\n",d);
getch();
}
The result was 6


According to the operation rule of Duhao expression: from left to right, the value of the whole expression is the value of the rightmost operands. But for this case, the operands are comma expressions



The price of 4 pens is equal to that of 6 ballpoint pens. A ballpoint pen is 6 yuan cheaper than a pen. How much is the unit price of the two pens?
Please solve it within 20 minutes. If it is within the deadline, you will be rewarded!


Suppose the unit price of ballpoint pen is X Yuan and that of pen is (x + 6) yuan
4(X+6)=6X
4X+24=6X
6X-4X=24
2X=24
X=12
X + 6 = 12 + 6 = 18 yuan
A: the unit price of ballpoint pen is 12 yuan, and that of pen is 18 yuan



If the height of a cylinder is increased by 3 cm, its surface area will increase by 18.84 cubic cm. What is the volume of the original cylinder?


What is the circumference of the base of the cylinder
18.84 △ 3 = 6.28cm
What is the base radius of the cylinder
6.28 ﹣ 3.14 ﹣ 2 = 1cm
The original volume of the cylinder is
1 × 1 × 3.14 × 5 = 15.7 cm3



What happens to me when I run at the speed of light? Faster than light? If I want to go to the future?


When you run in the form of a beam of light, time will fly. People are made of atoms, and the electrons moving around the atoms are the speed of light
Suppose that if a person really exceeds the speed of light, it will decompose. It's not old uncle AI who said that the speed of light can't be reached. Just like the lower limit of temperature
However, according to the theory, when the speed of light is reached, time will be still. Beyond the speed of light, we can go back to the past. Just like taking a cable car, we can only see the scenery outside, not touch it, let alone hope to rewrite history. Of course, even what we see is just a fake, just because of different reference systems
Hearsay's folly



The wire rope of the crane is used to lift heavy objects, and the force of heavy objects is compared: when the heavy objects rise at a constant speed, the pulling force increases_____ Gravity; pulling force when a weight falls at a constant speed______ Gravity; the pulling force of an object when it decelerates and rises______ Gravity (select "greater than", "less than" and "equal to")
(please explain why? I'm very tangled now!)


Equal to or less than
The first two have a uniform velocity and are balanced according to the two forces, so they are equal to
The third one is shifting



A rectangular paper is 20 cm long and 16 cm wide. How many square centimeters is its area? If you cut this rectangular paper into a small square with a side length of 4 cm,
How many pieces can you cut at most


What is the area
20 × 16 = 320 (cm2)
You can cut it
320 (4 × 4) = 20 (pieces)



Simple calculation: 7 * 11 of 12 + 7 of 12, 7 * 49 of 8, 3 * 9 of 8, 35 * (1 of 4 + 1 of 3)


7 / 12 * 11 + 7 / 12
=7/12x(11+1)
=7/12x12
=7
7 out of 8 * 49 out of 3 * 8 out of 9
=7/8x8/9x3/49
=7/9x3/49
=1/21
35 * (1 / 4 + 1 / 3)
=(36-1)x(3/12+4/12)
=36x7/12-1x7/12
=21-7/12
=20 and 5 / 12



Given the function f (x) = ι x ι + ι X-1 ι, find the range of the function


When x < 0: F (x) = - x-x + 1 = - 2x + 1, monotone decreasing, range (∞, 1)
When 0 ≤ x < 1: F (x) = x-x + 1 = 1
When x ≥ 1: F (x) = x + X-1 = 2x-1, monotone increasing, range [1, + ∞)
In conclusion, the range [1, + ∞)



Figure 6 is a rectangular grassland, 32 meters long and 24 meters wide, with a 2 meter wide path in the middle. Calculate the area covered by grass


Suppose the path is moved to the left (or right) side and the upper (or lower) side of the grass respectively,
Then 32 × 24 = 768 (M2)
The road is 2m wide
The total area of the path is (32 + 24) × 2 = 112 (M2)
The area covered by grass is 768-112 = 656 square meters
A: the area covered by grass is 656 square meters