The value of expression 16 / 4-2 ^ 5 * 8 / 4mod5 / 2 is () a 14 B 4 C 20 D 2

The value of expression 16 / 4-2 ^ 5 * 8 / 4mod5 / 2 is () a 14 B 4 C 20 D 2

The answer is b.4
16/4-2^5*8/4 MOD 5/2
STEP1:16/4 =4
Step2: 2 ^ 5 * 8 / 4 = the 5th power of 64'2 multiplied by 8 divided by 4
Step3: 5 / 2 = 2 'rounding;
Step 4: 64 mod 2 = 0 'mod operation, for floating-point numbers, round off operation
STEP5:4-0 =4

Let int b = 2; the value of the expression (b > > 2) / (b > > 1) is a) 0 b) 2 c) 4 d) 8

B = 2; / / b = 0010b binary
(b > > 2) / / 1 moved out, the result is 0
(b > > 1) / / the result is 0001b when 0 is moved out, and the result is 1
Of course, 0 / 1 equals 0
The answer is a

1. Calculate 1 + 2-3 + 4-5 + 6-7 + 8-9 + 10-11 + +1992-1993 + 1994

Original formula = 1 + (2-3) + (4-5) + ······ + (1992-1993) + 1994
=1+996×（-1）+1994
=1-996+1994
=999

Given A1 = 3,2an = 2A (n-1) + N in sequence {an}, find the general term formula of sequence {an}

An = 3 + (n + 2) (n-1) / 42an = 2A (n-1) + N2a (n-1) = 2A (n-2) + n-1.2a2 = 2A1 + 2 add the above n-1 formulas to 2 (an + a (n-1) + a (n-2). + A2) = 2 (a (n-1) + a (n + 2). + A2 + A1) + (n + 2) (n-1) / 2, so 2 (an-a1) = (n + 2) (n-1) / 2, an = 3 + (n + 2) (n-1) / 4

A conference room needs to be paved with square bricks. It needs 600 square bricks with an area of 0.09 square meters. If it is replaced with square bricks with a side length of 0.6 meters, how much will it take

First calculated area = 0.09 × 600 = 54 square meters
54 △ 0.6 & sup2; = 54 △ 0.36 = 150 pieces
A: about 150 yuan

What's one and a half plus two and a third plus three and a quarter plus four and a fifth plus five and a sixth plus six and a seventh plus seven and a eighth?

8321/280

Given sin (π / 2 + a) = 12 / 13 (- π / 2 ＜ a ＜ 0), find the value of COS (a - π / 6),

sin(π/2+a)=cos(a)=12/13
cos(a)=12/13
Because (- π / 2)

In a 1:600 drawing, the area of a square grassland is 10 square centimeters, and the actual area of this grassland is () square meters

Actual area: 10x600x600 = 3600000 square centimeters = 360 square meters

The non negative numbers a, B, C satisfy a + B + C = 30, 3A + B-C = 50, and find the maximum and minimum of n = 5A + 4B + 2C
Every step of the specific process of operation! One step is indispensable!

3a+3b+3c=90,3a+b-c=50
So n = 140-a
From the solution of a + B + C = 30, 3A + B-C = 50
b=40-2a
c=a-10
Because a, B, C are nonnegative
So 40-2a ≥ 0, a ≤ 20,
a-10≥0,a≥10
So 120 ≤ n ≤ 130
The maximum and minimum values are 130 and 120, respectively

In F (x) = x3-3x K, G (x) = (2kx-k) / (x2 2) x ^ 2 / A ^ 2 y ^ 2 / b ^ 2 = 1, spf1f2 = B ^ 2 * Tan β / 2
COSA COSB COSCx| |y-2/1|=0

0 (BCCA AB) / 2m =, n = relative D, so | x | = 0, | Y-2 / 1 | = 0 relative 0 (BCCA AB) / 2