11. Let a = b = D = true, C = e = false, the following logic operation expression value is true, there is () B.(((A∧B)∨C)∧D∧E) Why is B true ∧ true ∧ false? The result should be false?

You're right. Let's see if there's something wrong with the title, such as brackets
(((1∧1)∨0)∧1∧0)
= ((1∨0)∧1∧0)
= (1∧1∧0)
= (1∧0)
= 0

If the variable has been correctly defined and assigned, the expression in accordance with C language syntax is A.A = 2 + + B.A = 3,5 C.A = a + 1 = 3 d.12.3% 4
Can I get the remainder of that decimal?

No, the answer should be B, where the value of a is 3 and the following 5 doesn't work

How to read the sign of partial derivative

∂: the symbol of partial differential, (# 8706;) read as round invented by the French. The English translation of partial derivative is partial derivative, so it is sometimes read as partial. There is another way of reading, read as round & # 8706;: it is the classical writing of the Greek letter δ. In mathematics, it is only used as the sign of partial derivative

1m, 1dm, 3cm = () M

1m, 1dm, 3cm = (1.13m)

If the opening of the parabola is upward and the vertex coordinates are p (1,3), then the function y decreases with the increase of the independent variable x, and the value range of X is（
If the opening of the parabola is upward and the vertex coordinates are p (1,3), then the function y decreases with the increase of the independent variable x. the value range of X is ()

(－∞,1】

Given the quadratic function f (x) = the square of AX + BX + C f (- x + 5) = f (x-3) f (2) = 0 and the equation f (x) = x has equal roots, the analytic expression of F (x) can be obtained
RT
From F (- x + 5) = f (x-3), we can get the symmetry axis X = 1 of quadratic function, that is - B ＼ 2A = 1. Why?
Is there a real number m, n (M

From F (- x + 5) = f (x-3), we can get the symmetry axis of quadratic function x = 1, that is - B ＼ 2A = 1
From F (2) = 0, 4A + 2B + C = 0
From F (x) = x, we can get the square of (B-1) - 4ac = 0
A = - 1 ＼ 2, B = 1, C = 0 can be obtained by combining the above three algebraic expressions

Then (A2-B2) / (B-A) (b-2a) + (2A2 AB) / (4a2-4ab + B2) * (2a + b) / (2a-b)=

A & sup2; + ab-b & sup2; = 0A & sup2; + AB + B & sup2; + 4 - B & sup2; = 0 (a + B / 2) & sup2; - 5B & sup2; = 4 = 0 (a + B / 2 - √ 5B / 2) (a + B / 2 + √ 5B / 2) = 0A = (√ 5-1) B / 2 or a = (- √ 5-1) B / 2A / b = (√ 5-1) / 2 or a / b = (- √ 5-1) / 2 (rounding off, a and B are all positive numbers) (a & sup2)

There are two points D, E on the hypotenuse BC of the right triangle ABC, and be = AB, CD = AC. when the angle cab = 120 °, the degree of the angle DAE is calculated

There is no mistake in the title, but ABC is not a right triangle
The result is 30 degrees
Because there is no place to pass pictures, it is inconvenient to say so. I will say this to see if you can understand:
Angle BAE + DAE = BDA = DAC + ACD
Angle DAE + DAC = AEC = ABC + BAE
Add the above two expressions left and right:
BAE+DAE+DAC + DAE= DAC+BAE+ ABC+DCA
Bae + DAE + DAC = cab = 120;
DAC+BAE=120-DAE
ABC+DCA=180-120=60
Therefore, 120 + DAE = 120-dae + 60
So, 2x DAE = 60
DAE=30

What percentage is 37 out of 40

37 / 40 = 0.85, equal to 85%

There is a sports field with a semicircle at both ends and a rectangle in the middle. Find out the perimeter and area of the sports field. It is 80 meters long and 50 meters wide

Perimeter of sports field = perimeter of circle + 2 lengths of rectangle
3.14×50+80×2
=157+160
=317 (m)
Area of sports field = area of circle + area of rectangle
3.14×（50÷2）²+80×50
=1962.5+4000
=5962.5 (M2)

11. Let a = b = D = true, C = e = false, the following logic operation expression value is true, there is () B.(((A∧B)∨C)∧D∧E) Why is B true ∧ true ∧ false? The result should be false?