3. Assuming that all variables are integers, the values of the expression (a = 2, B = 5, B + +, a + b) are () (1 point) a, 7 B, 8 C, 6 D, 2

3. Assuming that all variables are integers, the values of the expression (a = 2, B = 5, B + +, a + b) are () (1 point) a, 7 B, 8 C, 6 D, 2

The answer is 8

1. Let integral variable a be 5, and the expression of B not be 2 is () A.B = A / 2 B.B = 6 - (- a) C.B = a% 2 D = b = a > 3? 2:1

Man, how can this be a single choice? B and C are obviously not 2. The final value of option B is 11, and that of option C is 1
If it's a single choice, it's estimated that the content of option B is wrong. It should be B = 6 - (-- a). There should be two minus signs in the brackets, so the result will be 2. Then, the final answer is only one, C

If a and B are integral variables, then the expressions a = 3, B = 2, and the values of a & B are

This is a logic and operation to convert a and B to binary numbers
A = 3 binary: 0011 (last 4 bits)
B = 2 binary: 0010 (last 4 bits)
So a & B is: 0 01 1
&0 0 1 0 up and down & operation 0 & 1 = 0 1 & 1 = 1
---------------------------------
Results: 0 0 1 0 was converted to decimal 2

How many jin is a kilogram

One kilogram equals two Jin

Given that the domain of definition and value of function f (x) = loga (x + 1) are [0,1], then the value of real number a is [0,1]___ ．

The definition field is [0, 1], so x + 1 ∈ [1, 2] and the value field is [0, 1]. Because the function f (x) = loga (x + 1) is a monotone function, the function value of the left end point of the definition field is 0, so loga (1 + 1) = 1, a = 2, so the answer is 2

The front of a commodity is a circle with a diameter of ACM and a square hole with a side length of BCM in the middle. How many square centimeters is the front area of this ancient coin

The area of the front of the coin = the area of the circle - the area of the square
= π*（a/2）^2 - b^2
= πa^2/4 - b^2

If the power factor of an inductive load is 0.5, connected to a 220 V sinusoidal AC power supply and the current is 10 A, the power consumed by the load is ()
I hope the answer will be more detailed

Apparent power = IV = 220 * 10 = 2200vi
Active power = 0.5 * 2200 = 1100vi
The power consumed by the load is active power, so the answer is 1100 watts

If {1,2} ⊆ a ⊆ {1,2,3,4,5}}, then the number of sets a satisfying the condition is ()
A. 6B. 7C. 8D. 9

⊆ {1,2} ⊆ a ⊆ {1,2,3,4,5}, ⊆ set a must contain 1 and 2 elements, so the set a satisfying the condition is {1,2}, {1,2,3}, {1,2,4}, {1,2,5}, {1,2,3,4}, {1,2,3,5}, {1,2,4,5}, {1,2,3,4,5} with a total of 8

If the line segment AB is known, extend it to AB to point C so that BC = half AB, extend AB to point d so that ad = three-thirds AB, CD = 26, and calculate the length of ab

Let AB length be a, then 26 = a + 2A / 3 + A / 2, a = 12, that is, AB length is 12

Ladder matrix is how to define, can give a few examples of ladder matrix. There are simplified ladder matrix

If the matrix a satisfies the following conditions: (1) the zero row (the row with all zero elements) is at the bottom; (2) the column label of the first non-zero element (that is, the first non-zero element of the non-zero row) increases strictly with the increase of the row label, then the matrix A is called a ladder matrix, such as: 579 6062 55008 if the matrix A also satisfies the following conditions: (...)