LIM (x → 0) ln (1 + x ^ 2) / sec x-cos

LIM (x → 0) ln (1 + x ^ 2) / sec x-cos

=As shown in the figure:

X tends to 0 Lim arcsin (TaNx / x)

lim(x→0)arcsin(tanx/x)
=lim(x→0)arcsin[(sinx/x)/cosx]
=arcsin1
=2nπ+π/2 (n=0,1,2...)

The solution set of inequality (3-x) (x + 2) < 0 is

Inequality (3-x) (x + 2) < 0 can be reduced to 3-x > 0, x + 2

The solution set of inequality x-3 / X-2 < 0 is

x-3/x-2＜0
(x-3)(x-2)

Let a random variable (x, y) have a probability density f (x) = 1 / 8 (x + y), 0 ≤ x ≤ 2, 0 ≤ y ≤ 2, then calculate ρ XY

Using MATLAB to solve multiple equation of one variable, such as x + x ^ 6 = a, a is a constant, how to solve x

solve('x+x^6=5')

What is a number that adds 7 minus 7 times 7 divided by 7 and finally equals 7

Let this number be X
(x+7-7)*7/7=7
The solution is x = 7

The bottom of a parallelogram is 5 meters. If the bottom of a parallelogram is extended by 1 meter, the area will be increased by 1.5 square meters. What is the area of the figure now

Height = 1.5 △ 1 = 1.5m
Current area = (5 + 1) × 1.5 = 9 square meters

Given the vertex P of quadratic function y = x square - 4x plus m, we can find the value of m on the line y = - 4x-1
【2】 Let the image and X intersect at two points A.B [point a is measured on the left of point B] and Y intersect at point C to find the area of the quadrilateral ACBP

The vertex coordinates are (2, M-4), so m = - 5
A (- 1,0), B (5,0), C (0, - 5), P (2, - 9). The area is 30

If x 2 - 2 (K + 1) x + K 2 + 5 is a complete square expression, find the value of K
I don't quite understand, teach~

Original = [x - (K + 1)] ^ 2 complete square
Then (K + 1) ^ 2 = k ^ 2 + 5
k^2+2k+1=k^2+5
k=2
^2 is the square