From the equation 1 / 2-3x = 2x + 1, we can get [urgent... I don't have any points]

From the equation 1 / 2-3x = 2x + 1, we can get [urgent... I don't have any points]

X=-1/10

It is known that the product of (x + 2) and (x's square + ax + b) does not contain a binomial formula of X, and the binomial formula is used to find the value of a and B

(x + 2) * (square of X + ax + b)
=x^3+ax^2+bx+2x^2+2ax+2b
=x^3+(a+2)x^2+(2a+b)x+2b
Binomial, binomial without x
a+2=0
a=-2
2a+b=0
b=-2a=4

There is a quadratic trinomial x square + 2x + 3. If it is multiplied by a binomial ax + B, there is no quadratic term in the product, and the coefficient of the first term is 2?
There is a quadratic trinomial x square + 2x + 3. If it is multiplied by a binomial ax + B, there is no quadratic term in the product, and the coefficient of the first term is 2,
Find the value of a and B

(x2 + 2x + 3) (AX + b) = AX3 + 2ax2 + 3ax + bx2 + 2bx + 3B = AX3 + (2a + b) x2 + (3a + 2b) x + 3B because there is no quadratic term in the product and the coefficient of the first term is 2, so 2A + B = 0 (1), 3A + B = 2 (2) (2) - (1) get a = 2, substitute a = 2 into (1) get b = - 4 answer: the value of a is 2, the value of B is - 4

Using the definition of derivative, find the derivative function of y = √ 2x + 1
It's defined by derivative

I don't see it very clearly. Give me three possibilities
y=(√2)x+1
y'=lim[h→0] [√2(x+h)+1-√2x-1]/h
=lim[h→0] (√2x+√2h-√2x)/h
=lim[h→0] √2h/h
=lim[h→0] √2
=√2
y=√(2x)+1
y'=lim[h→0] {√[2(x+h)]+1-√(2x)-1}/h
=lim[h→0] [√(2x+2h)-√(2x)]/h
=lim[h→0] 1/h*[√(2x+2h)-√(2x)][√(2x+2h)+√(2x)]/[√(2x+2h)+√(2x)]
=lim[h→0] 1/h*(2x+2h-2x)/[√(2x+2h)+√(2x)]
=lim[h→0] 1/h*2h/[√(2x+2h)+√(2x)]
=lim[h→0] 2/[√(2x+2h)+√(2x)]
=2/[√(2x)+√(2x)]
=1/√(2x)
y=√(2x+1)
y'=lim[h→0] {√[2(x+h)+1]-√(2x+1)}/h
=lim[h→0] [√(2x+2h+1)-√(2x+1)]/h
=lim[h→0] 1/h*[√(2x+2h+1)-√(2x+1)][√(2x+2h+1)+√(2x+1)]/[√(2x+2h+1)+√(2x+1)]
=lim[h→0] 1/h*(2x+2h+1-2x-1)/[√(2x+2h+1)+√(2x+1)]
=lim[h→0] 1/h*2h/[√(2x+2h+1)+√(2x+1)]
=lim[h→0] 2/[√(2x+2h+1)+√(2x+1)]
=2/[√(2x+1)+√(2x+1)]
=1/√(2x+1)

Simple calculation of 8.16 + 5.44 * 8.16 + 8.16 * 3.56

8.16×（1+5.44+3.56）=81.6

14 / 7 / 15-2 / 5 =? 4 / 2 + 2 / 3 =? 5 / 3-1 / 8 =? 3 / 6?

14 / 7 / 15-2 / 5
=14 of 7 and 15-6 of 2 and 15
=5 and 8 / 15
Two and four fifths + three and two thirds
=2 and 15 / 12 + 3 and 15 / 10
=6 and 7 / 15
Three and five sixties - one and five eighties
=20 of 3 and 24-15 of 1 and 24
=2 and 5 / 24

How to divide 2 (x-1) into x, x ^ 2-1 into 5, 3 (X-2) ^ 2 into 4

x/2(x-1)
5/(x+1)(x-1)
4/3(x-2)^2
I wonder if you copied the last question wrong

A score is divided into two parts, three parts, seven parts, and finally one fifth. Do you know what the original score is

Molecule 1x2x3x7 = 42
Denominator 5x2x3x7 = 210
It turns out that the score is 42 / 210

Square to 16______ ，______ The cube of is - 8

∵ (± 4) 2 = 16, the number of 16 is ± 4; (- 2) 3 = - 8

If x = 6, y = - half, z = 1, is the solution of the equation ax-6y = 333x + by = 16 2x-4y = CZ, then a =, B =, C=

The values of X, y and Z are carried in order to get. 6a-6 * (- 1 / 2) = 33. A = 5; 3 * 6 + b * (- 1 / 2) = 16, B = 4; 2 * 6-4 * (- 1 / 2) = Z; Z = 14