2 / 3 of (0.125) + (3 / 2 of 2) + 4 / 3 of + 2 - 1 + log2 3

2 / 3 of (0.125) + (3 / 2 of 2) + 4 / 3 of + 2 - 1 + log2 3

(0.125)^(2/3) + [2^(3/2)]^(4/3) + 2^(-1+Log2 3)
=[(1/2)^3]^(2/3) + 2^(3/2*4/3) + 2^(-1) * 2^(Log2 3)
=(1/2)^2 + 2^2 + 1/2 * 3
=1/4+4+3/2
=23/4

How many meters is 10000 square meters?
Worried about my IQ, how many meters is a square meter?

Meter is the unit of length, square meter is the unit of area. There is no comparability

How many meters is 10000 square meters equal to

Area and length are not interchangeable!

How much Oz is 12.5g

Oz as a unit of weight, divided into constant and golden / drug balance
If you're talking about Changheng, 12.5g = 0.4409 oz
Found this utility software: smart measurement unit converter
There are 95 units of length, area, volume and weight,
China Mobile Market: Unit Converter

The length of train a and train B are 144 meters and 180 meters respectively. Train a travels 4 meters more per second than train B. (1) it takes 9 seconds for the two trains to run in opposite directions, from meeting to staggering. How many seconds does it take for the two trains to run in the same direction?

If x + (x + 4) × 9 = 144 + 180, then x is 16 and a's speed is 20

If the mean of data 1, 2, 2, X is the same as the mode, then x is equal to ()
A. 1B. 2C. 3D. 4

According to the meaning of the question: 5 + X4 = 2, the solution is x = 3, so choose C

The ratio of their speed is 3:4. When the two cars meet, they are 20km away from the midpoint of AB, so as to find the distance between the two places

1. Because the speed ratio of a and B is 3:4, when meeting, the distance of a and B is also 3:4
2. That is to say, a drives 3 △ 3 + 4 = 3 / 7 of the whole journey; B drives 4 △ 3 + 4 = 4 / 7 of the whole journey
3. Because they met 20 kilometers away from the midpoint, B drove 20 + 20 = 40 kilometers more than a
4. 40 ÷ (4 / 7-3 / 7) = 280 km, and the distance between AB and ab is 280 km

Simple calculation 1 / 2 - (1 / 2-1 / 4) - (1 / 4-1 / 8) - (1 / 8-1 / 16) - (1 / 16-1 / 32) - (1 / 32-1 / 64)
If you answer right before 9:00, give it to 10:00

Solution
1/2-(1/2-1/4)-(1/4-1/8)-(1/8-1/16)-(1/16-1/32)-(1/32-1/64)
=1 / 2-1 / 2 + 1 / 4-1 / 4 + 1 / 8-1 / 8 + 1 / 16-1 / 16 + 1 / 32-1 / 32 + 1 / 64
=1/64

On the map with a line scale of 0.204060km, the distance between a and B is measured to be 2.5cm. How many kilometers is the actual distance between a and B?
It's really urgent

According to the scale, the ratio of the distance on the map to the actual distance is 1:2000000, that is to say, the distance on the map is 1cm, the actual distance is 2000000cm, that is, the distance on the map is 1cm, the actual distance is 20cm
Then the distance from a to B is: 2.5 × 20 = 50 ㎞

Given that O is the origin, a and B are two points on the parabola y ^ 2 = 2x, and OA ⊥ ob, the minimum value of s ⊥ OAB is obtained

This is simple,
Let OA be y = KX, (k > 0); let ob be y = (- 1 / k) X. (∵ OA ⊥ OB)
The intersection of straight line OA and parabola y ^ 2 = 2x at O and a points, substituting y = KX into y ^ 2 = 2x to get x = 0 or x = 2 / (k ^ 2), and the point a obtained from straight line OA equation is (2 / (k ^ 2), 2 / K
As above, the straight line ob intersects with the parabola at O and B, and y = (- 1 / k) x is substituted into y ^ 2 = 2x to get x = 0 or x = 2K ^ 2. From the straight line ob equation, the point B is (2k ^ 2, - 2K)
|OA|=√{[2/(k^2)]^2+[2/k]^2}=(2/k)·√[(1/k^2)+1],
|OB|=√{[2k^2]^2+[-2k]^2}=(2k)·√[k^2+1],
therefore
S△OAB=(1/2)·|OA|·|OB|
=2·√{[(1/k^2)+1]·[k^2+1]}
=2·√[k^2+1/(k^2)+2]
=2·√{[k+(1/k)]^2}
=2 · [K + (1 / k)] ≥ 4, if and only if k = 1 / K, i.e. when k = 1, the equal sign is taken
In conclusion, the minimum value of s △ OAB is 4