If the image of exponential function y = f (x) d passes through point (2,4), then f (4) f (4)=

If the image of exponential function y = f (x) d passes through point (2,4), then f (4) f (4)=

Exponential function y = f (x = a ^ x)
The image passes through points (2,4), that is, a ^ 2 = 4
a=2
f(x)=2^x
f(4)=2^4=16

If the function image of exponential function y = f (x) passes through the point, (2,4), find the value of F (4)

f(x)=a^x,4=a^2,a=2,f﹙x﹚=2^x,f﹙4﹚=2^4=16

It is urgent to draw the image of exponential function with absolute value. For example, y = | log5x | how to draw this image?

Log5x. OK
Just flip the image below the Y axis of the function along the X axis

For help, f (x) = x3-3x K, G (x) = (2kx-k) / (X22) y = x ^ 3x-2
A:B=B:C=31n（M N）=1nM 1nM

2y-x = 4Y = the square of x 1 / 2 of X - x 2 {x is unequal - 1 because √ a 2 - √ B 2 = √ [A-B] because 2y-x = 4

A rectangular piece of land is 35 meters long and 120 meters in circumference. How many square meters is the area of this piece of land?

35×（120÷2-35）
＝35×25
＝875

Given that M + n = - 3, the square of M + the square of n = 7, then the cube of M + the cube of n =?
Given that M + n = - 3, the square of M + the square of n = 7, then the cube of M + the cube of n =?
Like last time, the faster the points, the more``

m^3+n^3=(m+n)^3-3m^2-3mn^2=(-3)^3-3mn(m+n)=-27-3mn(-3)=-27+9mn
Because m ^ 2 + n ^ 2 = (M + n) ^ 2-2mn = (- 3) ^ 2-2mn = 9-2mn = 7, so Mn = 1
So m ^ 3 + n ^ 3 = - 27 + 9mn = - 18

The special solution of the differential equation y '+ 2Y / x + x = 0 satisfying y (2) = 0 is y = if sin2x is a primitive function of F (x), then the indefinite integral XF (x) DX=
The special solution of differential equation y '+ 2Y / x + x = 0 satisfying y (2) = 0 is y=
If sin2x is a primitive function of F (x), then the indefinite integral XF (x) DX=
I forgot all about Gao Shu

The special solution of differential equation y '+ 2Y / x + x = 0 satisfying y (2) = 0 is y = - x + 1
If sin2x is a primitive function of F (x), ∫ f (x) = sin2x + C, f (x) = 2cos2x,
∫xf(x)dx=∫x2cos2xdx=∫xd（sin2x）=xsin2x+∫sin2xdx=xsin2x-1/2cos2x+C

Five good words and sentences about strawberry
Come on, five. All right+

The strawberry is tender and juicy, delicious and sweet in shape, fragrant and strong in taste. It is full of raspberry, beautiful, tender and sweet. There are many small seeds on the surface of strawberry. When I was a child, I thought it was a lot of sesame sticking on it. The top is sharp, the end is round and big, just like the usual "love" pattern

The volume of a cone is 8 cubic decimeters, the bottom area is 4 square decimeters, and its height is () decimeters
Answer quickly

8 × 3 △ 4 = 6 (decimeter)

Add appropriate operation symbols and brackets in the formula to make the equation hold. Use five 0.5 to equal 2

(0.5+0.5)/0.5+0.5-0.5 = 1/0.5 = 2