To solve the problem of the system of linear inequalities of one variable, we must calculate it Example: 5x + 2 > 5 9x+6

5X+2>5
5X>5-2
5X>3
X>3/5
9X+6

I want to ask you to help me solve this problem with the system of linear inequalities of one variable,
The seventh grade of a school generally plans to divide the whole class into several groups to carry out mathematical inquiry activities. If there are 3 students in each group, there are 10 students left. If there are 5 students in each group, there is only one student in one group at most. The number of groups and the number of students in the class are calculated by inequality group

If plan group x is set, the number of people will be 3x + 10
0≤3x+10-5(x-1)≤1
That is, 0 ≤ - 2x + 15 ≤ 1
It is 7 ≤ x ≤ 7.5
So x = 7
3x+10=31
A: it is planned to be divided into 7 groups with 31 students

8.8 + 8.88 + 8.888 + 8.8888 + 8.88888 + 8.8888888 + 8.8888888 + 8.88888888 =? Find the integer part. What simple method can be used to get the answer?

His integral part is equal to the integral part of 8 × 8 + 0.8 × 8 + 0.08 × 8 = 64 + 6.4 + 0.64 = 71.04
That is 71
Because the latter is not enough to go into one
So the integral part is 71

Given the set a = {x | x2 + ax + 12b = 0}, the set B = {x | x2-ax + B = 0}, satisfying (∁ UA) ∩ B = {2}, a ∩ (∁ UB) = {4}, u = R, find the value of real numbers a and B

Because (CUA) ∩ B = {2}, a ∩ (cub) = {4}, so 2 ∈ B, 4 ∈ a, 4 − 2A + B = 016 + 4A + 12b = 0, a = 87B = − 127

Simple calculation of 136 × 101-136 by recurrence equation

136×101-136
=136×(101-1)
=136×100
=13600

If for any allowable value in a certain range, P = | 1-2x | + | 1-3x | + +|If the value of 1-9x | + | 1-10x | is constant, then the value is ()
A. 2B. 3C. 4D. 5

Since 2 + 3 + 4 + 5 + 6 + 7 = 8 + 9 + 10, the value range of X is: 1-7x ≥ 0 and 1-8x ≤ 0, that is, 18 ≤ x ≤ 17, so p = (1-2x) + (1-3x) + +(1-7x) - (1-8x) - (1-9x) - (1-10x) = 6-3 = 3

Given TN = n / N + 1, it is proved that 1 / 2 is less than or equal to TN

Because n > 0, so [n / (n + n)] ≤ n / (n + 1) < n / N = 1, that is, 1 / 2 ≤ TN

Excuse me: given that equation x ^ 2 + 4x + P = 0 and equation 2x ^ 2-3x + P = 0 have the same root, find the value of P

x^2+4x+p=0--> 2x^2+8x+2p=0
2x^2-3x+p=0
By subtracting the two equations, we get: 11x + P = 0, so the common root x = - P / 11
From the first equation, the other root is: - 4 + P / 11
So: (- P / 11) (- 4 + P / 11) = P >, P = 0 or - 77

How much is three fifths divided by zero forty-eight

3/5÷0.48
=3/5÷12/25
=3/5×25/12
=5 / 4 = 1 and 1 / 4
Or:
3/5÷0.48
=0.6÷0.48
=1.25

To solve the problem of the system of linear inequalities of one variable, we must calculate it Example: 5x + 2 > 5 9x+6