1. To satisfy x + 4 at the same time

1. To satisfy x + 4 at the same time

Moon: the reflection of the moon
1、
x＋4＜2x＋1 ①
1/2≤8－(3/2)x ②
By solving inequality 1, we get the following results
x＞3
By solving inequality 2, we get the following results
x≤5
∴3＜x≤5
The integer solutions are: 4,5
2、
Suppose he answers to question x, then:
10x－5(20－x)≥95
The solution is: X ≥ 13
A: he should answer at least 13 questions correctly

(2-3 / 4 × 4 / 5) / (1 / 12 + 4 / 15) simple calculation!
Today!

(2-3/4×4/5)÷(1/12+4/15)
＝(2-3/5)÷(5/60+16/60)
＝7/5÷21/60
＝7/5x60/21
=12/3
=4

How about factorization
1. Square of (x-5x) - 8
2.X(X-1)(X-2)(X-3)-24
3. Square of m-2mn + square of n-5m + 5N + 6
4.2a-5ab-3b + A + 11b-6
I'm a junior one. I don't want any radical. Ordinary cross multiplication is OK

1. (square of x-5x + 2 radical 2). (square of x-5x-2 radical 2)
2. (the square of x-3x-4) (the square of x-3x + 6)
3.(m-n-2)(m-n-3)
4 (2a+b-3)(a-3b+2)

98 divided by 7

98÷7=14 14x7=98

If the points a (3, - 2) and B (- 5,4) are known, the equation of the circle with the diameter of line AB is______ ．

Because point a (3, - 2), B (- 5, 4), so the midpoint coordinate formula of line AB is C (- 1, 1), that is, the coordinates of the center of the circle; r = | AC | = (3 + 1) 2 + (− 2 − 1) 2 = 5, so the equation of the circle is: (x + 1) 2 + (Y-1) 2 = 25. So the answer is: (x + 1) 2 + (Y-1) 2 = 25

Solve the equation 6 + 7 / 10x = 12 2 / 3x + 3 / 5x = 12 x divided by 5 / 8 = 10 / 17

6+7/10X=12
7/10X=6
X=6÷7/10
X = 60 / 7 (8 and 4 / 7)
2/3X+3/5X=12
19/15X=12
X=12÷19/15
X=12×15/19
X = 180 / 19 (9 / 19)
X divided by 5 / 8 = 10 / 17
X=10/17×5/8
X=25/68
Hope it works for you

Let a = {0}

0＜x-m＜3
m＜x＜3+m
So a = {x | m ＜ x ＜ 3 + m}
(1)
If a ∩ B = &;
Then m ≥ 0
3+m≤3
The solution is m ≥ 0
m≤0
So m = 0
(2)
If a ∪ B = b
Then 3 + m ≤ 0 or m ≥ 3
The solution is m ≤ - 3 or m ≥ 3

Simple calculation of (3 / 29 + 1 / 13) × 13 × 29

(3/29+1/13)×13×29
=(3/29+1/13)*13*29
=3/29*13*29+1/13*13*29
=39+29
=68

If XY > 0 and X + Y > 0, which quadrant is the point P (x, y) symmetrical about the origin

XY > 0 and X + Y > 0
So x > 0, Y > 0
So p is in the first quadrant
So the symmetry point of P about the origin is in the third quadrant

One half minus one quarter minus one eighth until 256

One half minus one quarter minus one eighth until 256
=1/2-1/4-1/8-…… -1/256+1/256-1/256
=1/2-1/2+1/256
=1/256