Find the answer to the exercise paper about the relationship between the root and coefficient of quadratic equation of one variable

Find the answer to the exercise paper about the relationship between the root and coefficient of quadratic equation of one variable

1、 (2, 6 2, - 1 / 3 3, - 1 / 3 3, - 1 / 3 3, - 1,4,39,11,11,5, 2 / 96, 28, 7, 5, 8, 03 / 22) make two pieces as x1, x2x1 + x2 = K + 1, X1 * x2 = 1 / 4K & \35\\35\35\35\\35\35\\35\\\\\\\\\\\\\\\\\\\\\\\\\ ∵

Exercises on the relationship between the root and coefficient of quadratic equation of one variable
If there are two real number roots α β for the quadratic equation x & # 178; + 2 (M + 3) x + M & # 178; + 3 = 0 with real coefficients of X, then what is the minimum value of (α - 1) &# 178; + (β - 1) &# 178?

1) Δ = 4 (M + 3) ^ 2-4m ^ 2-12 > = 0 m > = - 12) α ^ 2 + β ^ 2-2 (α + β) + 2 = (α + β) ^ 2-2 α * β - 2 (α + β) + 23) by Weida's theorem, we get α + β = - 2 (M + 3) α * β = m ^ 2 + 34) 3) 2) 2) 2) 4 (M + 3) ^ 2-2m ^ 2-6 + 4m + 12 + 2 and 2 (M + 7) ^ 2-54

The problem of quadratic equation of one variable in the third grade of junior high school
Example 1 on page p63 solves the steps in its steps
Square of 325 (1 + x) = 637
The square of (1 + x) = 1.96
1 + x = plus or minus 1.4
X1=0.4 X2=-2.4
Why is the square of (1 + x) = 1.96, and then the next step is equal to 1 + x = plus or minus 1.4? How can I find out this movie? Who can help me solve it? I don't know

1.96 square root, that is, 1.96 under the positive and negative root sign, resulting in a positive and negative 1.4

How many jin is five liter peanut oil
I want a more accurate answer,

Cut the crap
In a word, 9.2 Jin
No more formulas

If a ^ 2-6a + 9 and | B-1 | are opposite numbers, then the value of (A / B-B / a) / (a + b) is_____
The result of calculation: x + 1 / X-1 - x ^ 2-2x / x ^ 2-1 / X-2 / x ^ 2 + 2x - + is______ .
The result of calculation: (1 / X-2 - 1 / x + 2) * x ^ 2-4 / X is______ .
When x = 3-radical 2, the value of (x-1-8 / x + 1) / x + 3 / x + 1 is______ .

According to the meaning of the title: (A-3) &# 178; + | B-1 | = 0
∴a=3,b=1
The original formula = (3-1 / 3) / 4 = 2 / 3
I don't understand the order of the second question
Original formula = 4 / (X & # 178; - 4) * X & # 178; - 4 / X
=（4x²）/（x²-4）-4/x
=（4x³-4x²+16）/（x²-4）
Original formula = (x + 2 - 8 / x) / x + 1
=（2x+2-8/x）/x
=2+2/x-8/x²
=2 + 2 / (3-radical 2) - 8 / (9 + 2-6 radical 2)
=2 + 2 (3 + radical 2) / 7 - 8 (11 + 6 radical 2) / 49
=2 + (6 + 2 radical 2) / 7 - (88 + 48 radical 2) / 49
=(98 + 42 + 14 root 2-88-48 root 2) / 49
=(52-34 radical 2) / 49

If the resistance is 0 in a superconducting circuit, according to u = IR, is the voltage not 0?
If the reactance is 0

Your idea is right. In superconducting circuits, Ohm's law is still applicable. According to u = IR, when the resistance is 0 and there is current flowing through the conductor, the voltage at the two ends of the conductor is 0. This is correct. But in practice, we need to understand what electricity is used for. People don't want to use electricity, but want to convert electricity into electricity

A particle starts to move in a straight line with uniform acceleration from static state, and the acceleration is A1. After time t, it moves in a straight line with uniform deceleration, and the acceleration is A2. If the particle just returns to the original starting point after time t, then A1 ∶ A2 should be A1 ∶ A2

S1=0.5*a1*t^2
v1=a1*t
t2=v1/a2
S2=0.5*a2*t2^2
S3=0.5*a2*(t-t2)^2
There is a formula S1 + S2 = S3
a1：a2=1：3

Junior high school physics formula, only need formula, do not need to explain what is
You don't need to write too much, just write a simple formula

V=s/t
I=U/R
P=UI=I2R=U2/R
P=w/t
w=UIt=I2Rt=U2t/R
ρ=m/v
FlL1=F2L2
G=mg
P=F/s
P=ρgh
F = ρ GV = g row
μ = w yes / W total = GH / Fs
Q=mq=vq
Q=cmΔt

A long board B with mass m of 4kg is still on a smooth horizontal plane. A small slider a with mass m of 1kg is placed at the right end of the board
A. B moves to the left and right respectively with v = 2m / s. finally, a just doesn't slide away from the board B. given that the dynamic friction coefficient between a and B is μ = 0.4. G = 10m / S 1, we can calculate the acceleration a A and B 2 when a moves, and the displacement x 3 when a moves relative to the ground when a's relative velocity to the ground is zero, and the length L of B can be obtained

(1) For slide a, according to Newton's second law f = ma, we can know μ MAG = MAAA, so the acceleration of slide a is AA = μ g = 0.4 * 10 = 4 (M / s), similarly the acceleration of board B is ab = μ g = 0.4 * 10 = 4 (M / s) (2) according to the acceleration formula a = (vt-v0) / T, we can know t = (vt-v0) / a = (0-2

In a simple circuit, the supply voltage is u, there is a resistor R1 in the circuit, and the current passing through the ammeter is I1. If the current passing through becomes 3i1, then
What is the resistance R2 in parallel with R1?

According to the meaning of the title, after parallel connection, U / R total = 3i1, 1 / R total = 1 / R1 + 1 / R2, that is, 1 / r2 = 1 / R total - 1 / R1
R2 = 1 / (1 / R total - 1 / R1) r total = u / 3i1 R2 = 1 / (3i1 / U-1 / R1)