What is the least common multiple of 10,15,18,24

What is the least common multiple of 10,15,18,24

The least common multiple of 10,15,18,24 is 540

Because x △ 7 = y △ 6 (x, y are not equal to 0), X and y are proportional

x/y=7/6 !

It is known that the corresponding points of rational numbers a, B, C on the number axis are shown in the figure, where the corresponding points of B, C on the number axis are symmetrical about the origin, which is simplified as | B-A | + | a + C | - 2 | C-B |

From the position of the point on the number axis: C < 0 < B < A, | a | > | C |, | B-A < 0, a + C > 0, C-B < 0, then | B-A | + | a + C | - 2 | C-B | = A-B + A + C + 2 (C-B) = A-B + A + C + 2c-2b = 2a-3b + 3C

A sequence is composed of an equal ratio sequence and an equal difference sequence. How to find the sum

Common high school sequence summation types 2011-08-01 20:38 (1) arithmetic sequence, proportional sequence, binomial summation use the formula and binomial theorem. (2) the general term is equal difference * equal difference, which requires summation by groups. For example, the general term an = (n + 1) * (n + 2) sequence is used to find the first N-term summation

Given the function f (x) = 2 √ 3sinxcosx + 2cos & # 178; X-1 (x ∈ R), find the maximum and minimum values of function f (x) in the interval [0, π / 2]

F (x) = √ 3sin2x + cos2x = 2 (√ 3 / 2sin2x + 1 / 2cos2x) = 2 (COS π / 6sin2x + sin π / 6cos2x) = 2Sin (2x + π / 6) because x ∈ [0, π / 2] so 2x + π / 6 ∈ [π / 6,7 π / 6] so sin (2x + π / 6) ∈ [- 1 / 2,1] so 2Sin (2x + π / 6) ∈ [- 1,2] so the function f (x) is in the region

8 ^ 2008 multiplied by 125 ^ 2008 (- 81) ^ 10x (- 2 / 9) ^ 9x (1 / 9) ^ 10x (1 / 2) ^ 8x2 / 9
(- 81) ^ 10x (- 2 / 9) ^ 9x (1 / 9) ^ 10x (1 / 2) ^ 8x (2 / 9)

8^2008*125^2008
=(8*125)^2008
=1000^2008
=10^6024
(-81)^10*(-2/9)^9*(1/9)^10*(1/2)^8*2/9
=-4(-81)^10*(-2/9)^10*(1/9)^10*(1/2)^10
=-4(-81*(-2/9)*1/91*/2)^10
=-4(1))^10
=-4

There is a column of numbers, which are arranged into 1, - 2,4, - 8,16, - 32 Let the sum of three adjacent numbers be - 384, and find each of the three numbers

This is an equal ratio sequence with a common ratio of - 2. The latter number is - 2 times the former number
Let three adjacent numbers x, - 2x, 4x
x-2x+4x=-384
3x=-384
x=-128
-2x=256
4x=-512
So these three numbers are - 128256, - 512

The fourth power of a + the fourth power of B = a square - 2A square b square + b square. Find the sum of squares of a + B

The fourth power of a + the fourth power of B = a-2ab + B. the fourth power of a + the fourth power of B + 2Ab - (a + b) = 0 (a + b) - (a + b) = 0 (a + b) (a + B-1) = 0, so a + B = 0, or a + B = 1. If a + B = 0, then a = b = 0, so a + B = 0, if a + B = 1, then a + B = 0 can't be solved? Are there any other conditions?

3.3 solving linear equation of one variable (2) -- all answers without brackets and denominators
It must be all

Let's talk about going to the denominator first: for example, 2y-1 / 3 = y + 2 / 4
The least common multiple of denominator 3 and denominator 4 is 12, so 12 in the unary linear equation is divided by denominator, so 12 divided by 4 = 3, and then multiply 3 by each number of brackets (2y-1), and then y + 2 / 4 is the same as before. It is concluded that 4 (2y-1) = 3 (y + 2)
Then we remove the bracket 4 (2y-1) = 3 (y + 2): here 2 is multiplied by each item in the bracket (the front is - remove - and bracket, the inside changes to the opposite, remove + and the inside remains unchanged, for example: - 2 (x + 2)
Multiply 2 by each item in brackets, not negative 2. That one is left in brackets and used to enclose the book of Dharma. Then the answer to my question is 2y-1 / 3 = y + 2 / 4
Remove the denominator and get 4 (2y-1) = 3 (y + 2)
If we remove the brackets, we get 8y-4 = 3Y + 6
By shifting the term, we get 8y-3y = 6 + 4
That is 5Y = 10
y=2
I'm so sleepy. I'll add the rest next time

A column of numbers is arranged in a row a1a2a3,..., an,..., satisfying an + 1 = 1-1 / (an + 1),
If A1 = 1, then a2007 = ()
The analysis is as follows: from an + 1 = 1-1 / (an + 1),
We can get: 1 / (an + 1) - 1 / an, that is {1 / an} is an arithmetic sequence with tolerance of 1,
If the first item is 1 / A1 = 1, then 1 / a2007 = 1 / 2007
I can't understand why 1 / (an + 1) - 1 / an can be derived from an + 1 = 1-1 / (an + 1)
Why {1 / an} is an arithmetic sequence with tolerance of 1?

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