On the first grade Chinese topic of primary school: The sheep crawled and crawled. It was tired and couldn't move. It thought: I'm not afraid of being tired. How high the mountain is, how high I climb! How many sentences? Who can help me, please? But see the textbook, the teacher's decomposition of other sentences is to a comma, so I am very confused.

On the first grade Chinese topic of primary school: The sheep crawled and crawled. It was tired and couldn't move. It thought: I'm not afraid of being tired. How high the mountain is, how high I climb! How many sentences? Who can help me, please? But see the textbook, the teacher's decomposition of other sentences is to a comma, so I am very confused.

Look at the punctuation, the comma is not finished, the full stop is obvious, a sentence is finished (exclamation mark is the same)

June 1 children's Day is coming. If you are the host of the get-together, how can you host it? Please write it down.

Host's speech at the June 1 Party
1、 June is the season for dandelions to fall, for green apples to attract, for pomegranate flowers to light, and for singing. Oh, how wonderful the days in June are, how yearning the days in June are. Now, when spring girl's steps are fading away, The passionate summer girl is coming with a rainbow of seven colors! We are also looking forward to the "June 1" festival of our own!
2、 Today, we get together to celebrate children's Day! The party begins now
3、 Do you remember the wonderful scene of Li Wusong's fighting against tigers? Today, the tiger family is coming for revenge. It's said that they are going to have a fight. Let's welcome Yu Yan and Tang Boyu
4,
Female: let me ask you, do you know what dances Tai Lihua, a famous deaf mute dancer, dances?
Man: I only know about these two
Female: this time, there is a master dancer in the class who wants to compete with her. Do you want to watch? Let's invite sun Yiwen to perform
5、 June is the season of flowers blooming, the smell in the air, needless to say, Jiang Yiqin to sing this song for us
Six,
Man: my throat is itchy, I think
Woman: you don't want to sing, do you? Well, today I'll give you a chance to show it. Sing it. Welcome
7、 There are several small performers in the class who want to show off. First, they ask Jiang Yuqiu to bring us a piece, and then they ask Fei Fan to play a piece for us. This time, Cao Yuqiu, a heavyweight, plays a piece
8、 These three can really blow it. There are some more. Hey, isn't that Tom and Jerry? Let's see what they're going to do today
9、 A few days ago, the theme activity of math music is still going on. Rabbits, 12345 and foxes are all coming
10、 Jiangnan Water Town is very beautiful. Mo Di and Jiang Yiqin want to compare their beauty with it with their singing voice
Yu Yan was ill and got a terrible toothache. He went to a famous hospital in a hurry
11、 Ji Xiaolan, a big smokebag, loves to fight with Hekun. He is especially good at pairing. Recently, Jiang Yuqiu found out and got together to discuss it
12、 We also have a big game, called to touch, divided into four groups to throw gifts, please write your name and message on the gift, I'll talk about the rules
13、 Jia: today is the birthday of the big rectangle. All my friends come to congratulate me. What friends do you have to celebrate?
14、 Yang Zihao's Violin and Zhang shenglai's erhu are obvious to all. The melodious music brings us into a music hall. First, please ask Yang Zihao to play for us, and then ask Zhang shenglai to play for us
15、 Today, Gu Yi did badly in the exam. His mother threatened to beat him if he didn't quadruple his score
16、 Today is our festival. To celebrate our festival, please listen to the chorus
17、 Unconsciously, half a day has passed, let's seize this good time to study! And let's always remember this happy day! This is the end of the party

Given y = log (1 / 2) [a ^ 2x + 2 (AB) ^ X-B ^ 2x + 1] (A.B ∈ R +), find the value range of X that makes y negative
Given y = Log1 / 2 [a ^ 2x + 2 (AB) ^ X-B ^ 2x + 1] (A.B ∈ R +), find the value range of X that makes y negative

If y is negative, then:
a^2x+2(ab)^x-b^2x+1>1
a^(2x)+2a^x*b^x-b^(2x)>0
(a/b)^(2x)+2(a/b)^x-1>0
Let (A / b) ^ x = t,
t^2+2t-1>0
t√2-1
Because t = (A / b) ^ x > 0,
So the solution is: T > √ 2-1
(a/b)^x>√2-1
1, if a > b,
a/b>1
x>log(a/b) (√2-1)
2, if a = B,
a/b=1
x∈R.
3, if a

Design of JK Trigger and gate circuit counter in digital circuit experiment
RT is the design of synchronous counter. We need to design a 12 base counter, that is, from 01 - > 12 to return to 01. In this way, we hope someone can help us to analyze the idea and give us the circuit diagram,

JK flip-flop and gate circuit composed of synchronous counter circuit "and" count back to my alma mater - Experimental Primary School, I did not dare to go

In the formula 1R = R 1 + R 2, R 1 ≠ R 2, the formula for R 2 is obtained

∵1R＝R1+R2R1R2，∴R1R2=RR1+RR2，∴R1R2-RR2=RR1，∴R2=RR1R1−R．

In the expansion of (a-b) n times square, the binomial coefficient of the nth term is?

The binomial coefficient of the nth term CN (n-1) = CN (1) = n

Given a + B = - 5, ab = - 3, find a-Ab + B

A-Ab + B = a-Ab + B + 3ab-3ab
=Party A + 2Ab + Party B - 3AB
=(a + b) - 3AB
Bring in a + B and ab
Final result 34

In △ ABC, the opposite sides of angles a, B and C are a, B and C respectively. Given that B = π / 12 and C = B (1 + 2cosa), find the angle A

∵ C = B (1 + 2cosa), combined with sine theorem, it is easy to get: sinc = SINB (1 + 2cosa),
∴sin（A＋B）＝sinB（1＋2cosA）,∴sinAcosB＋cosAsinB＝sinB＋2cosAsinB,
∴sinAcosB－cosAsinB＝sinB,∴sin（A－B）＝sinB.
In △ ABC, it is obvious that: 0 ＜ a ＜ π, B = π / 12, ■ - π / 12 ＜ A-B ＜ 11 π / 12
From sin (a-b) = SINB = sin (π / 12), A-B = π / 12, a = B + π / 12 = π / 6

In high school mathematics dichotomy equation approximate solution, what is accuracy?
If the interval is (a, b) and the accuracy is 0.1, does the accuracy mean that | A-B | is less than 0.1 or B is less than 0.1

The root is at most 0.1 larger than a and 0.1 smaller than B

PX1 + x2 + X3 = 1, X1 + PX2 + X3 = P, X1 + x2 + PX3 = P & # 178; when p takes what value, the equation system has unique solution, no solution, infinite solution and general solution

The coefficient determinant | a | = (λ + 2) (λ - 1) ^ 2. Therefore, when λ ≠ 1 and λ ≠ - 2, the equations have unique solutions. When λ = 1, the augmented matrix = 1, 11, 11, 11, 11, 1r2-r1, r3-r111, 11, 11, 1, 1000, 000, then the equations have infinite solutions: (1,0,0) '+ C1 (- 1,1,0)' + C2 (- 1,0,1) '