Imitation of the first paragraph of the 17th "young man's leap soil" in the sixth grade volume I

Imitation of the first paragraph of the 17th "young man's leap soil" in the sixth grade volume I

There are golden leaves floating in the bleak autumn wind. Next to the old roof tiles, there are flaming red Parthenocissus like flowers. In the middle, there is an old man with flower armour. He has a young face with crane hair. He clenches his hands and pulls his back with his chest. His movements stretch out. It's amazing to do that
I hope I can help you. It's my honor to serve you

Chinese Vocabulary Manual grade 6 Volume 1 Lesson 17 draw inferences from one instance

1. Solemnity 2. Emphasis 3. Solemnity, disorder, no reason, no enemy, no sound, no reason, no reason, no compensation, no fear, no resistance
Hope to adopt

What is the little makes the most of the little
I don't have my word book with me! We're going to copy it!
grief

Clean up the open space, put up a bamboo plaque with a short stick, attach a rope, scatter chaff grain, and attract birds to pull the rope to cover the birds

The convenience fruit supermarket brought in a batch of apples. On the first day, it sold 14% of the total quality of the apples. On the second day, it sold the remaining 13. On the third day, it sold the remaining 12. At this time, there are still 120 kg left. How many kg are these apples?

120 △ 1-12 △ 1-13 △ 1-14, = 120 △ 12 △ 23 △ 34, = 120 × 2 × 32 × 43, = 480 (kg); a: this batch of apples is 480 kg in total

One half by two thirds by three fourths by four fifths is easy to calculate

Half by two-thirds by three-quarters by four fifths... By ninety-nine percent by ninety-eight percent by ninety-nine percent, the denominator of the first fraction and the numerator of the next fraction are approximately divided, and the final 99 percent is 1

R. The phase difference between total voltage and total current is known to be 30 ° and the inductive reactance is XL = 100 Ω=___________ Ω.
I want to know the calculation process

Tan30 = XL / R, r = 100 * 3 ^ 0.5 ohm

There are 46 students in class 6 (1), 44 students in class 6 (2) and 50 students in class 6 (3). The school allocates 70 books to each class according to the number of students in three classes. How many books should each class get?

Three classes 46 + 44 + 50 = 140 (person)
70 / 140 = 0.5 per person
One class: 0.5x46 = 23
2-shift 0.5x44 = 22 (this)
Three classes 0.5x50 = 25
If satisfied, remember to adopt!
Your praise is my motivation
(*^__ ^*(hee hee
I drink Coca Cola in the desert, sing karaoke, ride a lion, drive ants, and answer questions for you with a keyboard in my hand!

A is a real symmetric matrix and satisfies a ^ 2-3a + 2E = 0. It is proved that a is a positive definite matrix

I think we can use Kelley Hamilton theorem inversely, let Q be the eigenvalue and p be the eigenvector, then a * P = Q * P. multiply both sides of a ^ 2-3a + 2E = 0 by P, then (Q ^ 2-3q + 2) * P = 0, and P is not 0. Then we can solve q = 1,2. If all eigenvalues are greater than 0, then a is positive definite
There are many problems of this type, of course, there are other solutions, I can't recall them

It is specified that * is an operation symbol, and a * b = B power of a - a power of B
Then 4 * (3 * 2) =?

4*（3^2-2^3) = 4*(9 - 8)= 4*1=4^1 - 1^4 = 4 -1=3

When traveling by coach, one student noticed the milestone beside the straight road, and recorded the corresponding time. The data are shown in the table below
┌——————┬—————┬—————┬—————┬—————┬—————┐
The number of milestones is 10 km, 20 km, 30 km, 40 km, 50 km
├——————┼—————┼—————┼—————┼—————┼—————┤
The observation time is 6:30, 6:45, 7:20, 7:45
└——————┴—————┴—————┴—————┴—————┴—————┘
(1) Does the car move in a straight line at a constant speed? Why?
(2) Find the average speed of the car in the last 30 kilometers
The second question should explain the reason, use the prescribed steps to solve the problem, have solutions, known conditions, formulas, calculation process and answers
I'll take your answers in time. I need to answer them earlier. Thank you

(1) The car is not moving in a uniform straight line, because the same distance takes different time!
It should have been one hour in the last three hours of uniform acceleration,
15 + 20 + 25 = 60 minutes = 1 hour
If calculated by hour, then x = 30 / 1 = 30km / h
If calculated by minute, then x = 30 / 60 = 0.5km/min