English translation not reading with books, Full text: Not listening to the teacher in the class,not reading with books。

English translation not reading with books, Full text: Not listening to the teacher in the class,not reading with books。


Not reading with books is a little Chinglish
Not reading books concerning the class



I want to see some English translations of books about the highest figures in Chinese history


I want to read some books about supreme personage in China's history



What are the physical quantities represented by "H" in physics?


H is Planck constant, 6.62606876 × 10 ^ (- 34)
H V is the energy of a photon of frequency v
Is the minimum energy corresponding to the frequency v. it cannot be further divided



Mathematical logarithm operation
lg²4+lg²25+8lg2lg5


=4lg²2+8lg2lg5+4lg²5
=4(lg²2+2lg2lg5+lg²5)
=4(lg2+lg5)²
=4



Latitude position of Asia: south latitude, north latitude, west longitude and east longitude? Be precise!


The latitudes of Asia are as follows: 77 ° 43 'n, 11 ° 7's; 169 ° 40' W, 26 ° 3 'e, 169 ° 40' W, 60 ° 5 'n, 103 ° 30' e, 11 ° 7's, West to the Bering Strait



The general term formula of known sequence {an} is an = 6n-5 (n is odd number), 4 (n is even number). (above is piecewise function). Find the sum of the first n terms of sequence {an}
The key is to find the first 2n and s2n here


If n is odd, then the sum of odd terms is (6n-5 + 1) * (n + 1) / 2 / 2, and the sum of even terms is 4 * (n-1) / 2
If n is even, then the sum of odd terms is (6N-11 + 1) * n / 2 / 2, and the sum of even terms is 4 * n / 2



Finding the number of real roots of the square - [lgx] - 2 = 0 of the equation lgx


(lgx)²-|lgx|-2=0
|lgx|²-|lgx|-2=0
(|lgx|-2)(|lgx|+1)=0
|lgx|=2
X = 100 or x = 1 / 100
There are two real roots



How many seconds is an hour


3600



Observe and fill in the blanks. 100 × 100 equals 100 square equals 10000, 99 × 101 equals 100 square


Square 100 minus 1



The square of known polynomial (m-1) X3 power + 3x-nx + X-1 is quadratic binomial, which can be used to find the square of polynomial when m, N and x = 2


1, (m-1) x ^ 3 + 3x ^ 2-nx + X-1 = (m-1) x ^ 3 + 3x ^ 2 - (1-N) X-1 is a quadratic binomial, so M-1 = 0 and 1-N = 0 & nbsp; get: M = 1 & nbsp; n = 12, x = 2 substitute (m-1) x ^ 3 + 3x ^ 2-nx + X-1 to get & nbsp; 8 * (m-1) + 12-2n + 2-1 = 8m-2n + 5 = 8-2 + 5 = 11