Introduce something in a certain order (within 50) In the development of hundreds of years, Tibetan opera has formed its own inherent formula: the beginning tells the history of Tibetan opera to attract the audience, the main part of the story is performed, and the ending is meant to celebrate the success of the performance

Introduce something in a certain order (within 50) In the development of hundreds of years, Tibetan opera has formed its own inherent formula: the beginning tells the history of Tibetan opera to attract the audience, the main part of the story is performed, and the ending is meant to celebrate the success of the performance


In a person's life, the track of life is always accompanied by growth and harvest: when he is young, he is ignorant and curious, eager for knowledge; when he is middle-aged, he is experienced and mature, and ponders over life carefully; when he is old, he is skillful in human relations, and has a clear understanding of the world



Write a passage like this and introduce something in a certain order
In the course of hundreds of years of development, Tibetan opera has formed its own fixed pattern: the beginning tells the history of Tibetan opera to attract the audience, the main part of the story is performed, and the ending is meant to celebrate the success of the performance


For example: after everyone's exploration, the long jump has formed its own fixed program: the run-up is gradually accelerated from slow speed to obtain acceleration, the step jump is accurate without foul and loss, the acceleration is turned into upward and forward speed in the air, the landing is stable and the center of gravity is kept forward



There are three common ways to explain the order of things----------


Logical order
Spatial order
Chronological order



Solving the equation: the square of X - 6x + 9 = x-3


The square of X - 6x + 9 = x-3
(x-3)²=x-3
(x-3)²-(x-3)=0
(x-3)(x-3-1)=0
(x-3)(x-4)=0
x1=3 x2=4



The two vehicles a and B are facing each other from a and B at the same time. When they meet, they are 8 kilometers away from the center of a and B. It is known that the speed of vehicle a is 1.2 times that of vehicle B, and the distance between a and B is calculated______ Kilometers


Speed B: 8 × 2 ^ (1.2-1) = 80 (km / h); speed A: 80 × 1.2 = 96 (km / h); meeting time: 8 × 2 ^ (96-80) = 1 (H); distance between ab: (96 + 80) × 1 = 176 (km); answer: the distance between a and B is 176 km



It is known that the waist AB and AC of the isosceles triangle ABC are 5cm in length and 6cm in bottom edge. P is any point on the bottom edge, and the sum of the distances from P to the two waists is obtained


Let p to ab be x and AC be y
Then the area of triangle ABP is 5 * x / 2 and that of ACP is 5 * y / 2
So the area of triangle ABC is 5 * (x + y) / 2
From the combination of three lines of isosceles triangle, we can know that the height on the bottom BC is 4
So the triangle area is 6 * 4 / 2 = 12
We get 5 * (x + y) / 2 = 12, then x + y = 12 * 2 / 5 = 4.8



In the right triangle ABC, the angle c = 90 degrees, if a = 2, B = 3, then the square of C=__ Can C be an integer?


C's Square = 2's square + 3's Square = 13, so C = root 13, it can't be an integer, using Pythagorean theorem



40 workers in a workshop produce 10 parts a day. As a result, only 5 parts are unqualified. The qualified rate of this batch of parts is calculated


40 × 10 = 400, 400-5 = 395, 395400 × 100% = 98.75%. A: the qualified rate of this batch of parts is 98.75%



In a square paper with a circumference of 24 decimeters, cut the largest circle. How many square decimeters is the area of the cut part?


Second floor, the last data copy is wrong!
The perimeter of a square is 24, so its side length is 24 △ 4 = 6 decimeters
The circle is the largest, indicating that the diameter of the circle is 6 decimeters
Then the area of the cut part (that is, the area of the circle) = 6 * 6-3.14 * 3 * 3
=36-28.26
=7.74 (decimeter)



If the monomial - 3A ^ XB ^ 3 is the same as 1 / 3A ^ 2B ^ X-Y, find the value of Y ^ X


If the monomial - 3A ^ XB ^ 3 is the same as 1 / 3A ^ 2B ^ X-Y,
x+3=2+x-y
y=-1
y^x=(-1)^x
(1) X is even y ^ x = (- 1) ^ x = 1
(2) X is odd y ^ x = (- 1) ^ x = - 1