Xiaohong went to buy books and dictionaries and spent 30 yuan on story books, 20% more than dictionaries. At this time, the ratio of money already spent was 3:2. How much did Xiaohong bring with her?

Xiaohong went to buy books and dictionaries and spent 30 yuan on story books, 20% more than dictionaries. At this time, the ratio of money already spent was 3:2. How much did Xiaohong bring with her?

It costs 36 yuan to buy story books, a total of 66 yuan, which was 110 yuan
Story book money 30x1.2 = 36
It took 30 + 36 = 66
Money with = 66 divided by 3x5 = 22x5 = 110
A: Xiao Hong has 110 yuan in total
Hope to adopt o (∩)_ Thank you

Mr. Han bought a total of 10 dictionaries and story books for the students, which cost 210 yuan. The dictionary costs 35 yuan per book and the story book costs 15 yuan per book. How many dictionaries did Mr. Han buy? How many story books

10 times 35 is 350 yuan, 350-210 is 140 yuan. Storybook: 140 divided by 20 is 7. Dictionary: 10-7 is 3

A kind of ornamental vegetable, pocket pumpkin, buy 5 pots to get one free. Aunt Wang buy 5 pots at a time, how much cheaper is each pot?

30-30 × 5 △ 6 = 30-25 = 5 yuan. A: it's 5 yuan cheaper per pot

How to write the rules 3,4,1,3,4, (), 64,27, ()?
It's a fraction. It's written backwards
Class starts at 1 p.m

Is it 3-4,1,4-3, (16 / 9), 64-27, (256 / 81)
Equal ratio sequence with common ratio of 3 / 4

It is proved that when n is a natural number, n ∧ 5-N must be divisible by 30

N ^ 5-N = n (n ^ 4-1) = n (n ^ 2-1) (n ^ 2 + 1) = n (n-1) (n + 1) (n ^ 2 + 1) n (n-1) (n + 1) is the product of three consecutive integers. Obviously, n ^ 5-N can be divisible by both 2 and 3, so n ^ 5-N can be divisible by 6

If the image of exponential function f (x) passes through point (2, √ 2), then f (9)=

Because f (x) = a * x and because the image of exponential function f (x) passes through the point (2, √ 2), then a * 2 = (2 * 1 / 4) * 2, then f (x) = (2 * 0.25) * X
Then f (9) = 2 * (9 / 4)

I don't know how to do next or what to do next

All right
I don't know how to do next
I don't know what to do next
Generally speaking, the second kind of what to do is more accurate

Simplify m ^ 2-2m + 1 + m ^ 2-6m + 9 factorization 12x ^ 2 + 5x-2

m^2-2m+1+m^2-6m+9
=2m^2-8m+10
12x^2+5x-2
=(4x-1)(3x+2)

An applied problem of quadratic equation of one variable in the third grade of junior high school
This is not a very difficult one variable quadratic equation problem, the third problem is inevitable process!
Cut a 56cm long wire into two sections, and make each section into a square
(1) How to make the sum of the two squares 196cm?
(2) Can the sum of square areas be equal to 200 cm2?

If one segment is xcm, the other segment is 56-x
1. According to the meaning of the title
（X/4）²+[（56-X）/4]²=196
X = 0 or x = 56 are not suitable, so there is no solution to this problem
(3) Assuming that it can reach 200 cm & sup2;, then
（X/4）²+[（56-X）/4]²=200
→X²-56X-32=0
∵△=（-56）²-4×1×（-32）＞0
It's possible (it's just that an ordinary ruler can't measure it and has a root sign, so it's hard to cut it. It's possible)

On the 1:1000 scale school plan, a swimming pool is 5cm long and 3cm wide. How many square meters does the swimming pool cover?
It's the same equation, thanks

The swimming pool is x meters long and Y meters wide
5cm = 0.05m
0.05:x=1:1000
x=0.05×1000
x=50
3cm = 0.03m
0.03:y=1:1000
y=0.03×1000
y=30
50 × 30 = 1500 (M2)
A: this swimming pool covers an area of 1500 square meters
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