Aunt Zhang spent 34 yuan to buy 2kg apples and 2kg pears. It is known that the price of apples is twice that of pears, less than 0.7 yuan. How much is it per kilogram of pears

Aunt Zhang spent 34 yuan to buy 2kg apples and 2kg pears. It is known that the price of apples is twice that of pears, less than 0.7 yuan. How much is it per kilogram of pears


Let x yuan per kilogram of pear. 2x + (2x-0.7) * 2 = 34, x = 5.9



Aunt Zhang bought 392 kg of apples and pears, of which the weight of pears is six times that of apples. How many kg of pears and apples did she buy?


392 / (6 + 1) = 56 (kg)
392-56 = 336 (kg)
A: pear and Apple bought 336kg and 56kg respectively



Aunt Liu spent 14.2 yuan to buy the same one kilogram each. She asked how much each of the apples and pears cost for one kilogram?
Aunt Zhang spent 35.2 yuan on 2 kg of apples and 3 kg of pears, while Aunt Liu spent 14.2 yuan on 1 kg of apples and 1 kg of pears?


The linear equation of two variables is as follows
Let apple be a and pear be P
Then 2A + 3P = 35.2
A+P=14.2
The solution is a = 7.4, P = 6.8



The meaning of birch in the sixth grade book


Birch is a lyric poem by the famous Russian poet yesenin. The poem takes birch as the central image and describes its beauty from different angles. The snow covered, snow embroidered lace and white fringes are shining in the morning glow, covered with silver frost, blooming flowers, graceful and graceful, showing a kind of noble beauty



The least common multiple of 104 56 72


104=(2^3)*13;
56=(2^3)*7;
72=(2^3)*(3^2).
Therefore, the least common multiple is (2 ^ 3) * 13 * 7 * (3 ^ 2) = 6552



The ratio of X to 3 / 4 is equal to the ratio of 1 / 5 to 2 / 5


x:(3/4)=(1/5):(2/5)
2x=3/4
x=3/8



Please use counter examples to prove that the following propositions are false propositions:
(1) The sum of squares of any two real numbers is greater than zero
(2) If a, B and C are three points on the same line, then AB + BC = AC


1、0²+0²=0
2. C is the midpoint of the line AB, then AB + BC = 2Ac + AC = 3aC ≠ AC



It is known that a, B and C are equal difference sequence, and the tolerance is d (D ≠ 0); and C, a and B are equal ratio sequence, and the common ratio is Q, and d = q, so we can find a, B and C


a. The tolerance is db-a = C-B = DB = a + DC = a + 2dc, a and B are equal ratio series, the common ratio is QA / C = B / a = Q. substitute B = a + DC = a + 2D into a / (a + 2D) = (a + D) / A = QD = q, so a / (a + 2D) = D, a = AD + 2D ^ 2. If d = 1, then a = a + 2, does not hold, so D is not equal to 1, so a = 2D ^ 2 / (1-D) (a



Given x + 2Y = 5, xy = 5 / 2, find the square of (x-2y)!
Try to find (2 + 1) (2 + 1) (the fourth power of 2 + 1) (32nd power of 2 + 1) + single digit of 1


The square of (x-2y) = (x + 2Y) & sup2; - 8xy = 5 & sup2; - 8 × 5 / 2 = 25-20 = 5 (2 + 1) (2 & sup2; + 1) (the fourth power of 2 + 1) (32 power of 2 + 1) + 1 = (2-1) (2 + 1) (2 & sup2; + 1) (4 power of 2 + 1) (32nd power of 2 + 1) + 1 = (2 & sup2; - 1) (2 & sup2; + 1) (quartic power of 2 + 1) 2



A pedestrian is walking on the road. Every six minutes, a bus in the same direction passes by him. Every two minutes, a bus in the opposite direction passes by. People go straight on. The speed of cars and people is uniform
How often does a bus leave


Set the distance s, speed x, speed y between two buses in the same direction
X+Y=S/2
X-Y=S/6
The solution is: x = s / 3
S / x = 3 (min)
The train leaves every three minutes