What are Andersen's famous fairy tales

What are Andersen's famous fairy tales

Danish 19th century fairy tale writer and founder of world literature fairy tales. Born on April 2, 1805 in Odense, Denmark, his father was a poor shoemaker. He volunteered to serve against Napoleon Bonaparte's invasion and died in 1816. His mother, who was a laundryman, remarried soon. Andersen was tortured by poverty from childhood and worked as an apprentice in several shops, He had no formal education. When he was young, he became interested in the stage and dreamed of becoming a singer, actor or playwright. In 1819, he became a supporting actor in the Royal Theatre of Copenhagen. Later, he was fired for losing his voice. Since then, he began to learn to write, but the script he wrote was not suitable for performance and was not adopted by the theatre
The road of creation
In 1822, he was funded by theater director Jonas Colin and studied in a grammar school in sleuther. Hans Christian Andersen
In 1827, he published his first poem, the dying child, and in 1829, he wrote the book "the attempt of youth", which was published under the pseudonym of William Christian Walter. The pseudonym includes the names of William Shakespeare, Andersen himself and Scott, He entered the University of Copenhagen to study. His first important work, a walk from the Holmen canal to the east corner of AMEE island in 1828 and 1829, was published in 1829. It is a travel book full of humor and has the style of German writer Hoffman. The publication of this travel book made Andersen initially recognized by the society. After that, he continued to work in drama creation. In 1831, he went to Germany for a trip, He wrote travel notes on his way home. In 1833, he went to Italy and created a poetic drama "egnet and Mermaid" and a novel "impromptu poet" (1835) with Italian background. Soon after the novel was published, it was translated into German and English, marking that the author began to enjoy international reputation. In 1835, he began to create fairy tales and made great achievements, creating more than 200 fairy tales in his life
Representative works
"The daughter of the sea", "the ugly duckling", "the little match girl", "Thumbelina", "the emperor's new dress", "Tinder Box", "firm tin soldier", "wild swan", "red shoes", "Tinder Box", "wild swan", "Snow Queen", "shadow", "a drop of water", "mother's story", "puppet actor" and so on

The author of the fairy tale "the emperor's new clothes" is the world-famous Danish writer Andersen

The fairy tale the emperor's new clothes is the work of Andersen, a famous Danish writer
perhaps
The author of the fairy tale the emperor's new clothes is Andersen, a famous Danish writer

As we all know, Andersen, a famous Danish fairy tale writer, has written many fairy tales. Please introduce his fairy tale in 80 words

"Little Match Girl" tells the story of a little match girl who died in the street on the new year's eve of the rich people's family. The little girl died with a smile on her mouth. Through the beautiful fantasy of lighting a match, it forms a sharp contrast with her starving and cold real life

It is known that three vertices a (0, - 4) B (4,0) C (- 6,2) of △ ABC, and points D, e and F are the midpoint of edges BC, Ca and ab respectively
(1) Find a straight line DE.EF.FD The equation of
(2) Find the linear equation of the high line ch on the edge of ab

D(-1,1),E(-3,-1),F(2,-2)
k(DE)=k(AB)=1,k(EF)=(BC)=-1/5,k(FD)=k(AC)=-1
(1) Straight line:
DE:x-y+2=0
EF:x+5y+8=0
FD:x+y=0
(2)
k(AC)*kAB)=-1
The linear equation AC: where the high line ch on the edge of AB is located
x+y+4=0

How to use the phrase "in spit of"?

Noun or phrase
1.Linda is respective in spite of her AGE.
Her father was an old unmarried professor of mathematics, a brutal man and a braggart, who went out to give reasons in spice of his age
For in spite of her tender years and evidence delay health, she had an air of natural distinction
Though timid and weak, he has a natural and romantic attitude,

The sum of numerator and denominator of a simplest fraction is 86. If both numerator and denominator are reduced by 9, the reduced fraction is 8 / 9
Find the original simplest fraction

If both the numerator and denominator are subtracted by 9, then the sum of the numerator and denominator is subtracted by 18, that is, 86-18 = 68; the simplest fraction is 8 / 9, that is, 68 is divided into 17 parts, the denominator is 9 parts, 4 * 9 = 36, and the numerator is 8 parts, 4 * 8 = 32; then add the 9 subtracted before, that is 41 / 45

How to judge the stress of closed syllable words? Please give an example? Why do open, visit and listen not use double ending letters and prefer now? Don't copy other web pages

Stress closed syllable
Although open, visit and listen end with consonants, and the penultimate sound is a vowel, they are stressed on the first syllable, so there is no need to write double
Preference is stressed on the second syllable and the penultimate consonant is a vowel

In known isosceles trapezoid ABCD, ab = 3, BC = 2, CD = 1, find vector AB * vector ad, vector AB * vector DC, vector AB * vector BC

∵AB＝3　BC＝AD＝2　CD＝1
∴∠DAB＝∠ABC＝60°
The vector AB * the vector ad = ab · ad cos60 ° = 3 / 2
Vector AB * vector DC = ︱ ab ·︱ DC ︱ cos0 ° = 3
Vector AB * vector BC = ｜ ab ·｜ BC ｜ cos120 ° = - 3

Help solve several trigonometric function problems!
1、sinA+cosA=tanA,(0

It's too much trouble
Here's an idea
(Sina) ^ 2 + (COSA) ^ 2 = 1 and Sina + cosa = Tana
tana=sina/cosa
The calculation process is too complicated
Do it yourself
Second question
Have you learned the auxiliary angle formula
That is, Asina + bcosa = positive and negative (under the root sign (a ^ 2 + B ^)) sin (a + Φ)
Then Tan Φ = B / A
This question should be ok with this one
The third question
40=60-20
80=60+20
160=180-20
It's all about 20
I think so
Just apply sine and cosine of sum or difference of two angles

As shown in the figure, point E is any point on the edge of Cd in the square ABCD. EF ⊥ AE is at point E and intersects the edge of BC at point F. take point a as the center, rotate △ ade clockwise 90 ° to get △ Abe ′. Try to explain: EE ′ bisects ∠ AEF

It is proved that: ∵ ade is rotated 90 ° clockwise to get △ Abe ′, ≌ △ Abe ′, ≌ AE = AE ′, ≌ EAE ′ = 90 °, AEE ′ = 45 ° and ≌ - fee ′ = 90 ° = AEE ′, that is, EE ′ bisection ∠ AEF