3 / 5 × (4 and 1 / 5 + x = 7.2)

3 / 5 × (4 and 1 / 5 + x = 7.2)

3 / 5x (4 and 1 / 5 + x) = 7.2
4 1 / 5 + x = 7.2 / 3 / 5
4 and 1 / 5 + x = 12
X = 12-4 and 1 / 5
X = 7 and 4 / 5 or (7.8)

Is 2x / x + 2 reducible

No, I can't

Solving quadratic equation of one variable: (x-3) (x-3) = 4 (2x + 1) (2x + 1)

(x-3)(x-3)=4(2x+1)(2x+1),
That is, (x-3) & sup2; = [2 (2x + 1)] & sup2;,
Then x-3 = 2 (2x + 1), or x-3 = - 2 (2x + 1),
The results show that X1 = - 5 / 3, X2 = 1 / 5

Given a = 2B + 2 (a ≠ 1), find the value of (A & sup2; - 4B & sup2;) / (A & sup2; - 4B & sup2; + A + 2b) - A & sup2; + 4ab-4b & sup2;)

-10/3

The solution equation is: 5 and 12 / 7-x = 3 and 4 / 1-3 / 2x

5·7/12-x=3·1/4-2x/3
67/12-x=13/4-2x/3
Multiply both sides of the equation by 12
67-12x=39-8x
4x=28
x=7

Advanced mathematics, implicit function derivative calculation
The derivative of implicit function should be y '=?
The title is as follows: x ^ (2 / 3) + y (2 / 3) = a (2 / 3)

2 / 3x ^ - 1 / 3 + 2 / 3Y ^ - 1 / 3 * y '= 0, just move the term

Find the range of y = √ (x ^ 2-6x + 13) -√ (x ^ 2 + 4x + 5)

Solution y = √ (x-3) square + 4 -- √ (x + 2) square + 1
So x can take any straight drawing, we can see that when x = - 2, y has the maximum straight (√ 29) -- 1, when x = 3, y has the minimum straight 2 -- (√ 26)

Given that the absolute value of x = 4, X and y are opposite numbers, and x > y, find the square of the absolute value of X + 5 - (Y-3)

Solution
/x/=4
Ψ x = 4 or x = - 4
∵ X and y are opposite to each other
When x = 4, y = - 4
When x = - 4, y = 4
∵x>y
∴x=4,y=-4
∴/x+5/-(y-3)²
=/4+5/-(-4-3)²
=9-49
=-40

Given the equations of X and Y 2x − y = 32kx + (K + 1) y = 10 and X and y are opposite to each other, find the value of K

2x − y = 3, ① 2kx + (K + 1) y = 10, ②, ∵ from X and y are opposite numbers, ∵ x = - y, take x = - y ① to get - 2y-y = 3, and solve y = - 1, ∵ x = 1, and substitute x = 1, y = - 1 into ② to get 2k-k-1 = 10, and solve k = 11

How to find the integral of the whole of e x times SiNx

∫(e^x)sinxdx
=∫sinxd(e^x)
=sinx(e^x)-∫(e^x)dsinx
=sinx(e^x)-∫(e^x)cosxdx
=sinx(e^x)-∫cosxd(e^x)
=sinx(e^x)-(e^x)cosx+∫e^xdcosx
=sinx(e^x)-(e^x)cosx-∫e^xsinxd
So ∫ (e ^ x) sinxdx = (e ^ x) [SiNx cosx] / 2 + C