Chinese Grade 5 Volume 2 unit 2 picture composition The one at the football match

Chinese Grade 5 Volume 2 unit 2 picture composition The one at the football match

On a sunny afternoon, a group of boys happily went to the open space and threw their bags and hats into two piles, which became a simple goal. The fierce match began. The golden haired goalkeeper's face turned red because of tension and joy. Although his knee was scratched yesterday, he didn't care

Fifth grade volume two unit 2 picture composition
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One fine afternoon, under the horned melon tree at the end of the wheat field, a small football match was going on fiercely, attracting many audiences, including children and adults. Beside the low wall, there was a simple goal made of schoolbag and hat. In the middle of the goal, there was a steady small goal keeper. His skin was slightly brown, and he was wearing a black white-collar short sleeve shirt, Under a pair of green pants, there is a wound on his right knee, wrapped in white gauze. He squats, leaning forward slightly. His legs are crossed, his eyes are bright, looking forward, ready to jump forward to catch the ball. Behind him, there is a goalkeeper waiting for mending. He is wearing a red sportswear, and his mouth is wide open. He seems eager to fight. On the left is a long wooden bench, There are people watching the game on the bench. A black little boy hugs his little brother. They both watch intently. A pug who doesn't know is lying on the ground snoring. Next to them are three red scarves. The first little boy seems to be blocked by something and can't help bending down. The boy behind him stretches his neck, The little girl with a bow simply stood up; in front of her was a girl with a bundle of hair, holding her beloved doll, straight and flushed; in front of her was a big uncle, dressed in a suit and hat, with a smile on his face, as if recalling his childhood on the court, It's like a small shuttle weaving a golden tapestry. At this time, I only heard the sound of the wind and the water, and saw the silent secret of the flowers. We all watched the scene

People's education press Chinese Grade 5 Volume 2 unit 2 composition 450 words

On a sunny afternoon, a group of boys happily went to the open space and piled their bags and hats into two piles. The fierce match began. The golden haired goalkeeper's face turned red with tension and joy. Although his knee was scratched yesterday, he didn't care. He put his hands on his knee, The little boy standing behind him, dressed in a red sportswear and with a big stomach, was a little unconvinced. Yesterday, when his elder brother broke his leg, he kicked away a ball and won. He thought of it with some pride. Passers-by were attracted by the tense match. They stopped and sat on the bench, I don't know whose dog it is. It's not interested in football. It's only interested in the little ball provided by its owner. Now it's doing nothing but snoring on the grass. You see, the little boy with his younger brother is sitting on the yellow team with his eyes tightly, for fear that the yellow team will lose. The little boy with golden hair, like the goalkeeper, craned his neck, "Come on! Kick! Good!" the little girl standing behind him, with a crimson butterfly Festival tied on her head, stood up and saw her hands akimbo, her brows wrinkled, as if something was wrong. The little girl in the red hat bent over, stretched her head and looked to the right, her face turned red, Although she didn't go to the "battlefield", her heart beat clearly. A girl with a doll in her arms kept smiling, but her eyes were busy. She kept staring at the ball to see where the ball was in the team. Maybe it was the first time that the little boy in Green saw such a scene. His little hand was counting the outcome, and he gently waved his hand,

In trapezoidal ABCD, ad ‖ BC, diagonal AC and BD intersect at point O. if the area of △ AOB is equal to 4, then the area of △ cod is equal to 4

Because ad ‖ BC
So, s △ abd = s △ ACD
So, s △ cod = s △ AOB = 4

If lgx + lgx2 + lgx3 +... + lgx10 = 110, then lgx + lg2x +... + lg10x =?
The natural numbers 2,10 in lgx + lg2x +... + lg10x are several powers
I know the answer is 2n (the nth power of 2) - 2
Well, I'm really wrong. The answer is 2 to the 11th power minus 2. Sorry
But how can I do something different from the answer when I get x equal to 100

lgx+lgx2+lgx3+...+lgx10=110
Because lgx + lgx2 + lgx3 +... + lgx10 = lgx + 2lgx + 3lgx +... + 10lgx
So 55lgx = 110
lgx=2
But: lgx + lg2x +... + lg10x =?
I feel strange. How can I get an n?
I guess you're wrong
I think the following is the summation formula of equal ratio sequence
It's right to subtract 2 to the 11th power of 2, that is, to use the summation formula of the equal ratio sequence!

There are seven bamboo poles in a row. The first one is one meter long, and the other one is half of the former one. How many meters is the total length of this bamboo pole?

1+1/2+1/4+1/8+1/16+1/32+1/64=127/64

If (2a & sup2; + 3A + 7) is negative once = 1 / 8, find the value of 4A & sup2; + 6a-1 / 9
Quick quick quick quick quick quick quick quick quick quick quick quick quick quick quick quick quick quick quick quick quick quick quick quick quick quick quick quick quick quick quick quick quick quick quick quick quick quick quick quick quick quick quick quick quick quick quick quick quick quick quick quick quick quick quick quick quick quick quick quick quick quick quick quick quick quick quick quick quick quick quick quick quick quick quick quick quick quick quick quick

(2a & sup2; + 3A + 7) negative once = 1 / 8
2a²+3a+7=8
2a²+3a=1
4a²+6a=2
1/(4a²+6a-9)=-1/7

If the base of a triangle remains unchanged, the height will be doubled, and the area will be ()

2 times larger

Given that loga (x2 + 4) + loga (Y2 + 1) = loga5 + loga (2xy-1) (a > 0, and a ≠ 1), the value of log8yx is obtained

It is known that (x2 + 4) (Y2 + 1) = 5 (2xy-1), that is, x2y2 + x2 + 4y2 + 4 = 10xy-5, that is, (x2y2-6xy + 9) + (x2 + 4y2-4xy) = 0, that is, (xy-3) 2 + (x-2y) 2 = 0. Therefore, YX = 12. Log8yx = log812 = -13

To make a square bottomless water tank with a volume of 256l, what's its height and material saving?

Let the height of the tank be x and the length of the bottom edge be a, then a 2x = 256 and its surface area s = 4ax + a 2 = 1024a + a 2 = 512a + 512a + a 2 ≥ 33512a × 512a × a 2 = 3 × 26 = 192. If and only if a = 8, that is, H ﹥ 4, s gets the minimum