Under what circumstances can two triangles be proved congruent

Under what circumstances can two triangles be proved congruent


When an angle is a right angle, the HL theorem is used



Why can't edges and corners prove the congruence of triangles?


Make an isosceles triangle ABC, extend BC to D (any length) (AB = AC)
Connect ad
Triangle ADC
AB = AC ad = ad angle ADB = angle ADC
However, they are not all equal



The root common ()
A. 1 B. 2 C. 3 d. 4


∵ 1-z4 = 0, ∵ Z4 = 1, ∵ z = 1, - 1, I, - I & nbsp; can be selected



The third power of 4P (1-p) + the square of 2 (p-1)
Quick answer


4p(1-p)^3+2(p-1)^2
=-4p(p-1)^3+2(p-1)^2
=[(p-1)^2](-4p^2+4p+2)
=-2[(p-1)^2](2p^2-2p+1)



How to draw a rectangle with a circumference of 20 cm and a ratio of length to width of 2:1? Draw a triangle with a bottom of 5 cm and a ratio of height to bottom of 1:1


Rectangle length + width = 1 / 2, perimeter = 10, length 10 × 2 / 3 = 20 / 3, width 10 × 1 / 3 = 10 / 3
The height of the triangle is the same as that of the bottom. It's five centimeters long. Draw an isosceles triangle



The graph of a quadratic function passes through three points (0,0), (- 1, - 1), (1,9). The relation of this function is obtained


Let the relation of quadratic function be y = AX2 + BX + C (a ≠ 0), ∵ the image of quadratic function passes through three points (0, 0), (- 1, - 1), (1, 9), ∵ point (0, 0), (- 1, - 1), (1, 9) satisfies the relation of quadratic function, ∵ 0 = a × 02 + B × 0 + C − 1 = a × (− 1) 2 + B × (− 1) + C9 = a



In the polynomial 4x & # 178; + 1, add a polynomial to make it a complete square


It could be
-4x
4x
4x^4



If the length of a rectangle is reduced by 4cm, its area will be reduced by 20cm. If the width is increased by 3cm, its area will be increased by 12cm?


If the length is reduced by 4 cm, the area will be reduced by 20 square cm, and the width = 20 / 4 = 5
If the width is increased by 3 cm, the area will be increased by 12 square cm, and the length = 12 / 3 = 4
Rectangle area = 5 * 4 = 20 square centimeter



The minimum value of the function y = 1 / 3x ^ 3-4x + 4 is (), for detailed explanation


Let y '= x & # 178; - 4 = 0
x=±2
be
X2, y '> 0, increasing
-2



Find the derivative f (x) = (x ^ 3 + 2) ^ 10 * (x ^ 9-x ^ 4 + X + 1), find the derivative of order 40