1. Solve the equation X:Y=3:2 {Y:Z=5:4 X+Y+Z=66 2. In the equation y = ax ② + BX + C (x ② represents the quadratic power of x), when x = 1, y = - 4; when x = - 1, y = 0; when x = 2 and x = 0, the value of Y is equal. Find the value of a, B and C (the correct answer to the first question is x = 30, y = 20, z = 16; the correct answer to the second question is a = 1, B = - 2, C = - 3)!

1. Solve the equation X:Y=3:2 {Y:Z=5:4 X+Y+Z=66 2. In the equation y = ax ② + BX + C (x ② represents the quadratic power of x), when x = 1, y = - 4; when x = - 1, y = 0; when x = 2 and x = 0, the value of Y is equal. Find the value of a, B and C (the correct answer to the first question is x = 30, y = 20, z = 16; the correct answer to the second question is a = 1, B = - 2, C = - 3)!

1、
X:Y=3:2
X=3Y/2
Y:Z=5:4
Z=4Y/5
Substituting x + y + Z = 66
3Y/2+Y+4Y/5=66
3.3Y=66
Y=20
X=3Y/2=30
Z=4Y/5=16
2、
Put in three groups of numbers
-4=A+B+C (1)
0=A-B+C (2)
4A+2B+C=0+0+C (3)
(1)-(2)
2B=-4
B=-2
Substituting (3)
4A-4+C=C
A=1
Substituting (2)
C=B-A=-3
So a = 1, B = - 2, C = - 3

Add 20 points to the math problem of grade one in junior high school
1. Suppose the area of your school is 300m × 300m and the size of the drawing is 20cm × 30cm, what is the maximum scale you should choose?
2. If the train runs at the speed of 120 km / h, how long does it take to get from Beijing to Tianjin by train? (the distance on the picture is 3 cm)

130000 / 20 = 1500 scale, maximum 1:1500
2\
It is impossible to work out the scale of the map without giving it
Additional 20 points is not spoken, to be reflected in the reward points

1. We know that the m power of 2 is a, and the n power of 2 is B
Find the M + n power of 8, the M + n power of 2, the 3M + 2n power of 2
2. It is known that the power a of 2 is 3
B power of 2 = 6
C power of 2 = 18
What is the relationship between ABC and ABC?
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Please finish it before 1 o'clock, otherwise it's too late!

1. M + n power of 8 = (2 & sup3;) m + n power = (2 m + n power) & sup3; = (2 m power × 2 n power) & sup3; = A & sup3; B & sup3; 2 m + n power + 2 3M + 2n power = (2 m power × 2 n power) + (2 3M power × 2 2n power) = AB + (2 m power) & sup3; × (2 n power) & sup2; = a

If the numerator and denominator of a fraction are added with 13 at the same time, it can be reduced to 67 and the original fraction can be obtained

Let the denominator be x, and the numerator denote x-3. From the meaning of the question, we can get: & nbsp; X − 3 + 13X + 13 = 67 (x + 10) × 7 = (x + 13) × 6 & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; 7x + 70 = 6x + 78 & nbsp; 7x + 70-6x = 6x + 78-6x & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; X + 70 = 78-70 & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; X = 8; molecule: x-3 = 8-3 = 5; so the original score is 58; a: the original score is 58

Please find out the open syllable words and the closed syllable words in the following words
Open syllable words:
Closed syllable words:
and hand he tree new milk flu dark to too size jam late head from form peach catch june blue why whose rob robe tail till eve steve

There are two forms of open syllable
1. Absolute open syllable is a stressed syllable ending with a vowel letter. Its form is "consonant letter + vowel letter". The vowel letter is read as the letter sound of the vowel letter in the stressed absolute open syllable: a read / EI /, e read / I /, I (y) read / AI /, O read / &# 601; U /, u read / ju /, such as my / Mai /, go / G & # 601; U /, me / MI /, etc
2. Relative open syllable is a syllable ending with a consonant letter (except R) and a vowel letter e. it is in the form of "vowel + consonant + e". The vowel letter is read as the letter sound of the vowel in stressed relative open syllable. For example: make / meik /, time / tail /, huge / hju: dn /, mistake / MIS > teik /
The above open syllable words are as follows:
he tree flu dark to too size late blue june why whose tail eve steve
2. Closed syllable
A syllable ending with one or more consonants (except R) and having only one vowel in the middle is called a closed syllable. In stressed closed syllables, vowels read short sounds, i.e. a / A / A / E /, E / E /, I (y) read / I /, O read / כ /, u read / # / or / U /, e.g. desk / desk /, think / θ I & #331; K /, shop / ∫ כ P /, must read / m#st / etc
The above closed syllable words are as follows:
and hand milk jam head from form peach catch rob till

English translation
Unit 1 Section B 3a is translated,
That's OK. I've finished it. Let's talk about some good ways to learn physics

Do the experiment, observe the phenomenon and process of the experiment, but also remember the book knowledge, especially the concept of a large number of questions

High school mathematics How can we find the sum of vector AB + CD + EA + de + BC? How can we calculate it? Let's talk about it. Should we draw a picture to solve it?

AB+CD+EA+DE+BC
=AB+BC+CD+DE+EA
=(AB+BC)+(CD+DE)+EA
=AC+CE+EA=AE+EA=0

Exercises of trigonometric function in Mathematics
In square ABCD, e and F are the top two points of AD, EF = 3, Tan ∠ Abe = 1 / 4, Tan ∠ FBC = 8 / 5, find FD
Today or something, if there is no one, I will withdraw the question

3. It's very simple. Draw a vertical line from point F to BC, and the intersection point is g. let the side length of the square be x, then AE = 1 / 4 * x, BG = 5 / 8 * x, CG = 3 / 8 * x, natural DF = 3 / 8 * x, so there is 3 = X-1 / 4 * x-3 / 8 * x, x = 8, so FD = 3

What is the pronunciation of "Qi" in the word "Tieqi"? Why is "Ji" pronounced on TV and "Qi" only pronounced in the dictionary of modern Chinese by the Commercial Press

As shown in the figure, in square ABCD, e and F are two points on the edge of AB and BC, and EF = AE + FC, DG ⊥ EF is in G, proving: DG = da

Extend BC to H point, make ch = AE, connect De, DF, from AE = ch, ∠ DAE = ∠ DCH, ad = CD, △ AED ≌ △ CHD, ≌ de = DH, and ≌ FH = Fe, DF = DF, de = DH, ≌ △ def ≌ △ DFH, ≌ DG is the height of EF side in △ def, DC is the height of HF side in △ DHF, and EF, HF are congruent triangles