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1. Voltage is the cause of (). Under the condition of constant resistance, the current intensity in the conductor is the same as the voltage at both ends of the conductor ()
2. When the voltage is constant, the current intensity in the conductor is the same as the resistance of the conductor
3. The current intensity in a conductor is proportional to the voltage at both ends of the conductor and the resistance of the conductor. This conclusion is called (). The formula is ()
4. The characteristic of ammeter is resistance (). If the ammeter is directly connected to the two poles of power supply, () will be burnt out. The characteristic of voltmeter is resistance (). If the voltmeter is directly connected to the two poles of power supply, () (fill in "yes" or "no") will be burnt out
5. The resistance values of the two resistors are R1 = 12 ohm and R2 = 4 ohm respectively. If they are connected to the circuit in series, the ratio of current intensity through them is I1 ∶ I2 = (), and the ratio of resistance voltage is U1 ∶ U2 = ()
6. If two resistors R1 and R2 are connected in parallel, and the ratio of current intensity through them is I1 ∶ I2 = 3 ∶ 4, then the ratio of voltage at both ends of two resistors is U1 ∶ U2 = (), and the ratio of two resistors R1 ∶ R2 = ()
7. If the total resistance of two resistors with the same resistance in parallel is 40 ohm, the total resistance of them in series is ()
8. If the total resistance of two resistors with the same resistance in series is 40 ohm, the total resistance of them in parallel is ()
9. There is a wire with a voltage of 6 V applied at both ends, the current intensity passing through it is 0.6 a, and its resistance is (); if a voltage of 15 V is applied to it, the current intensity in the wire is (); at this time, the resistance of the wire is (); if the voltage at both ends of the wire is zero, the current intensity passing through it is (), and its resistance is ()（
10. When R 1 and R 2 are connected in series, the total resistance is 15 ohm. When R 1 and R 2 are connected in parallel, the total resistance is 3.6 ohm
12. If a resistor R1 with 4 ohm is connected in series with R2, the total resistance is 10 ohm, then R2 = (), if they are connected in parallel, the total resistance is ()
13. Resistance R1 ∶ R2 = 1 ∶ 2, if they are connected in series to the power supply, the ratio of voltage at both ends of them is (), the ratio of current intensity through them is (); if they are connected in parallel to the power supply, the ratio of voltage is (), the ratio of current intensity is ()
14. The total resistance obtained by series connection of N resistors with R is () times of that obtained by parallel connection
15. The voltage at both ends of a section of conductor is 6 V, the current intensity through the conductor is 0.4 a, and the resistance of the conductor is (). When the voltage at both ends of the conductor increases to 9 V, the current intensity in the conductor is (), the resistance of the conductor is (), and the voltage between the two conductors decreases to zero, the current intensity in the conductor is (), and the resistance of the conductor is ()
16. In the circuit, two lamps L1 and L2 are connected in parallel. Their resistances are 150 Ω and 450 Ω respectively. If the current intensity through L1 is 1.5 A, then the current intensity through L2 is ()
17. The total resistance of series circuit is greater than that of any conductor (); the total resistance of parallel circuit is greater than that of any conductor ()

As shown in the figure, in the circuit, R1 = 10 Ω, R2 = 20 Ω, and the power supply voltage is 6V, when K2 is closed and K1 and K3 are disconnected, the indication of the ammeter is______ The indication of the voltmeter is______ When K2 is open and K1 and K3 are closed, the indication of ammeter is______ The indication of the voltmeter is______ ．

(1) When K2 is closed, K1 and K3 are closed, the equivalent circuit diagram is as follows: the voltmeter measures the power supply voltage, so the indication is 6V; the current in the circuit I = ur1 + R2 = 6v10 Ω + 20 Ω = 0.2A; (1) when K2 is closed, K1 and K3 are closed, the equivalent circuit diagram is as follows: the voltmeter measures the power supply voltage, so the indication is 6V; on

Ohm's law second grade physics calculation problem
The resistance R1 and R2 are connected in series in the circuit, the voltage at both ends of R1 is 3V, the voltage at both ends of R2 is 9V, R1 + R2 = 600 Ω
1. Total voltage of current
2. Current in a circuit
3. Resistance value of resistance R1 and R2
If the answer is correct and clear, how much do you want to give

(1) Because it is a series circuit, so the total voltage in the circuit: u = U1 + U2 = 3 + 9 = 12 (V) (2) because it is a series circuit, so the total resistance of the circuit: r = R1 + R2 = 600 (Ω) the current in the circuit: I = u / r = 12 / 600 = 0.02 (a) (3) because it is a series circuit, so, I1 = I2 = I = 0.02ar1 = U1 / I1 = 3 / 0.0

Xiaowan's mobile phone received the following message: "think of a number, add 52.8 to it, multiply by 5, subtract 3.9343, divide by 0.5, and finally subtract ten times of the number in mind. The answer is very romantic!" According to the above instructions, let the number in Xiaowan's mind be x, and find out the romantic number

According to the meaning of the title, we get 10.5 [5 (x + 52.8) - 3.943] - 10x, = 2 (5x + 264-3.943) - 10x, = 520.1314

6x-8=4x+48
Calculate with equation
fast
There must be a process, otherwise how can I know it's 28

x=28

Two thirds of a number is 18. What's seven ninths of it?

21

Why (6x ^ 2-13x + 6) (2x ^ 2-5x + 2) = (2x-3) (3x-2) (2x-1) (X-2)

6x^2-13x+6=(2x-3)(3x-2)
2x^2-5x+2=(2x-1)(x-2)

How to calculate 1.46 * 0.5 + 8.54/2 with simple algorithm

1.46*0.5+8.54/2
=1.46*0.5+8.54*0.5
=(1.46+8.42)*0.5
=10*0.5
=5

If we know that a function of degree passes through point a (2,2) and is parallel to the line y = 2x + 1, then the expression of the function of degree is ()

y=2x-2

A number plus 55, multiplied by 6, minus 5, divided by 5, the final result is 5. What's the number?

Second grade, really. I haven't learned unknowns yet, have I
Add 55 to a number, multiply by 6, subtract 5, divide by 5, and the result is 5
The final result is 5 × 5 = 25
25+5=30
30÷6=5
5-55=-50
Take the previous information as a number in turn, and that's it