The minimum value of the square of Y X - 2aX + 1 when x is less than or equal to 1 and greater than or equal to 0

The minimum value of the square of Y X - 2aX + 1 when x is less than or equal to 1 and greater than or equal to 0

y=x²-2ax+1=x²-2ax+a²+1-a²=（x-a）²+1-a²
When a is less than or equal to 0, the minimum value of Y is x = 0, y = 1
When a is greater than 0 and less than 1, the minimum value of Y is x = a, y = 1-A & # 178;
When a is greater than or equal to 1, the minimum value of Y is x = 1, y = 2-2a

Given X & # 178; + 2x = 4 and 2mx & # 178; + 4mx-12 = 0 --- find 2m & # 178; + m?

x²+2x=4
2mx²+4mx-12=0
So 2m (X & # 178; + 2x) - 12 = 0
So 2m times 4-12 = 0
M=3/2
2m²+m
=2 times (3 / 2) square + (3 / 2)
=6