The cylinder with a diameter of 12 cm on the bottom is cut by a plane at 30 ° to the bottom. The section is an ellipse, and the major axis of the ellipse is long______ , short axis length______ The centrifugation is______ ．

The cylinder with a diameter of 12 cm on the bottom is cut by a plane at 30 ° to the bottom. The section is an ellipse, and the major axis of the ellipse is long______ , short axis length______ The centrifugation is______ ．

∵ the diameter D of the bottom surface of the cylinder is 12cm, and the cross section is 30 ° to the bottom surface. The short axis length of the ellipse is 2B = D = 12cm, and the long axis length of the ellipse is 2A = dcos30 ° = 83cm. According to C = A2 − B2, if the half focal length length of the ellipse is C = 23cm, then the eccentricity of the ellipse is e = CA = 2343 = 12

It is known that the two focuses of the ellipse e are F1 (- 1,0) F2 (1.0) point C (3 / 1,2) to find the equation of the ellipse E on the ellipse E. problem 2 if the point P is on the ellipse e, find the vector Pf1 * the vector PF2 = t and the value range of the real number t

(1) Given that the focus of the ellipse is on the x-axis, let e equation be X & # 178; / A & # 178; + Y & # 178; / B & # 178; = 1, a & # 178; - B & # 178; = 1, so a & # 178; = b & # 178; + 1, and point C (1,3 / 2) on the ellipse e, substitute it into the equation of E, and get 4B ^ 4-9b & # 178; - 9 = 0, and solve it to get B & # 178; = 3, so a & # 178; = 4, then the equation of E is X -

In the equation mx2-my2 = n, if Mn < 0, then the curve of the equation is ()
A. Ellipse with focus on X-axis B. hyperbola with focus on X-axis C. ellipse with focus on Y-axis D. hyperbola with focus on y-axis

In ∵ mx2-my2 = n, divide both sides of ∵ by n to get x2nm − y2nm = 1 ∵ Mn < 0, NM < 0. The standard equation of the curve is Y2 − nm − x2 − nm = 1, (- nm > 0) ∵ the curve represented by equation mx2-my2 = n is a hyperbola focusing on the X axis, so select: D

How many quasars are there for ellipse, parabola and hyperbola?
Such as the title

Ellipse and hyperbola have two quasars
A parabola has a straight line

Solving steps of quadratic inequality with one variable

First solve the equation AX & # 178; + BX + C = 0
The solution is x1, x2
Suppose X10
And a > 0
Then XX2
ax²+bx+c>0
And a

Detailed solving process of quadratic inequality of one variable
4+3x-x²＞0
x²-1≥0
x²-2x﹢24≥0
x²－4x＋9≤0
x²－2x＋3＞0
x²－2x－3≥0
﹣x²－3x＋4＜0
x²＋2x≤0
(x＋a)﹙x＋1﹚≥0

4+3x-x²＞0
x²-3x-4

Interval representation for solving quadratic inequality of one variable
1.4x²-12x+9＞0
2.2x²+4x+9＞0
3.x²-x＞x(2x-3)+2
4.x²-x≥0

Mojing 123: I can help you with this problem; the main thing is that you learn how to solve the problem... This kind of inequality of quadratic equation with one variable. First, it becomes an equation. Then, we can see if we can use cross multiplication to become (x-x1) (x-x2) = 0. If it is OK, it represents △≥ 0

To solve quadratic inequality of one variable, the solution set is represented by interval
x²-x+2>0

a=1>0
So the solution set of the original inequality is r

Must the solution of quadratic inequality of one variable be expressed by interval?

It can also be expressed by greater than or less than, but strictly speaking, it is an interval. Because the solution of the inequality must be within the range of real numbers. Even if you use greater than or less than to express it, your unknown number will still be labeled as a real number (x or Y ∈ R)

Solving quadratic inequality of one variable
X * - 9x + 14 is less than 0, find its value range!

x^-9x+14