If circle: x2 + y2-4x + 6y = 0 and circle: x2 + y2-6x = 0 intersect a and B, then the equation of the vertical bisector of AB is______ ．

If circle: x2 + y2-4x + 6y = 0 and circle: x2 + y2-6x = 0 intersect a and B, then the equation of the vertical bisector of AB is______ ．

The coordinates of the center of circle: x2 + y2-4x + 6y = 0 are (2, - 3), and the coordinates of the center of circle: x2 + y2-6x = 0 are (3,0). The equation of the vertical bisector of AB is the equation of the straight line where the centers of two circles are. The equation of the vertical bisector of AB is y + 30 + 3 & nbsp; = & nbsp; X − 23

Find a point P on the circle x ^ 2 + y ^ 2 = 4 to make the distance from P to the straight line 4x + 3Y = 6 maximum

4X+3Y=6
y=-4/3x+2
Its vertical slope is 3 / 4
Passing point (0.0)
y＝3/4x
This point is on the circle, so
X^2+Y^2=4
y＝3/4x
So the abscissa of this point is - 8 / 5
The ordinate is - 6 / 5

Point P is a point on the circle x ^ 2 + y ^ 2 = 4, and the distance from P to the straight line 4x + 3Y = 2 is the largest, then what is the coordinate of point P?

A circle is a circle with (0,0) as its center and 2 as its radius
The line intersects the circle and passes through one two four
Therefore, point P is a straight line perpendicular to the line 4x + 3Y = 2 and the intersection of the circle in the third quadrant
LIANLI
-4x+3y=2
x^2+y^2=4
If I'm right, P is (- 6 / 5, - 8 / 5)
You'd better do it yourself. I often make mistakes in my calculation