If there are only three points on the circle (x-1) ^ 2 + (y + 1) ^ 2 = 4 and the distance from them to the straight line 4x + 3Y = m is 1, then the value of M is?

If there are only three points on the circle (x-1) ^ 2 + (y + 1) ^ 2 = 4 and the distance from them to the straight line 4x + 3Y = m is 1, then the value of M is?

The distance from the point (1, - 1) to the straight line 4x + 3Y = m is 1
The formula of the distance from point to line is as follows:
Let P (x0, Y0), the linear equation be ax + by + C = 0
Then the distance from P to the straight line is: D = | ax0 + by0 + C | / √ (A & # 178; + B & # 178;)
Just calculate it yourself

Find the coordinates of the nearest point on the circle x2 + y2-4x-2y + 3 = 0 to x-y-5 = 0______ ．

Circle x2 + y2-4x-2y + 3 = 0, that is, (X-2) 2 + (Y-1) 2 = 2, the center of the circle is C (2,1), and the radius is 2. The equation of the straight line passing through the center of the circle C and perpendicular to x-y-5 = 0 is Y-1 = - 1 × (X-2), that is X + Y-3 = 0. From x + y − 3 = 0x2 + Y2 − 4x − 2Y + 3 = 0, we can get x = 1y = 2, x = 3Y = 0, as shown in the figure: so the coordinates of the nearest point from the circle x2 + y2-4x-2y + 3 = 0 to x-y-5 = 0 are (3, 0), so the answer is: (3, 0)