There is a rectangular sheet of iron, 24 cm long and 14 cm wide. Cut out the same small square at the four corners, and fold it to make a uncovered iron box, so as to find the capacity of the iron box The side length of the cube is 4cm

There is a rectangular sheet of iron, 24 cm long and 14 cm wide. Cut out the same small square at the four corners, and fold it to make a uncovered iron box, so as to find the capacity of the iron box The side length of the cube is 4cm

(24-2x)*(14-2x)*x
X is the side length of the truncated square

There is a rectangular sheet of iron, 32 cm long and 24 cm wide. The same small square is cut off at the four corners and folded to make a box without a cover
To make the area of the bottom of the box half of the original area, find the height of the box

Let the side length of a small square be X
The width of the river is 32-2x, 24-2x
It's half the size
2*(32-2x)(24-2x)=32*24
(x-16)(x-12)=96
x^2-28x+96=0
(x-24)(x-4)=0
Obviously 24-2x > 0, X