The square iron sheet with side length of 48 cm is used to make an iron box without cover
Let the side length of the truncated small square be a and the volume of the iron box be v
V=(48-2a)^2×a=4a^3-192a^2+2304a (0
Set up equations to solve application problems: a rectangular piece of iron is 25cm in length and 15cm in width. Now cut out a small square with equal side length from its four corners, and fold up the four sides to make a rectangular box with 231 square centimeters in floor area. Find out the side length of each small square to be cut out?
231=3*7*11=21*11=(25-4)*(15-4)
So the side length of the cut small square is 4cm