A factory uses rectangular and square cardboard as shown in figure a to make vertical and horizontal rectangular cartons as shown in Figure B

A factory uses rectangular and square cardboard as shown in figure a to make vertical and horizontal rectangular cartons as shown in Figure B

(1) Suppose x vertical cartons and (100 - x) horizontal cartons, square paper: vertical cartons = x, horizontal cartons = 2 * (100 - x), a total of X + 2 (100 - x) = 200 - x rectangular paper: vertical cartons = 4x, horizontal cartons = 3 * (100 - x), a total of 4x + 3 (100 - x) = 300 + X (2) square paper

A factory uses the rectangular and square cardboard as shown in the figure to make the vertical and horizontal cartons as shown in Figure B. they are two kinds of rectangular cartons without covers

（1）①x,3（100-x）
② According to the meaning of the title, x + 2 (100-x) ≤ 162; 4x + 3 (100-x) ≤ 340
The solution to the system of inequalities is 38 ≤ x ≤ 40, so x can be 38, 39, 40
Answer: according to the number of production of two kinds of cartons, there are three production schemes
(2) Because the two kinds of cardboard just ran out
So the number of horizontal cartons is (162-x) / 2
Because 290