The minute hand of a clock is 10 cm long and the hour hand is 8 cm long 1. From 12:00 to 2:00, how many cm does the minute needle tip pass? From 6:00 in the morning to 6:00 in the afternoon, how many cm does the hour needle tip pass? 2. What is the area swept by the clock from 6 am to 6 pm? What is the area swept by the clock from 12 am to 6 pm?

The minute hand of a clock is 10 cm long and the hour hand is 8 cm long 1. From 12:00 to 2:00, how many cm does the minute needle tip pass? From 6:00 in the morning to 6:00 in the afternoon, how many cm does the hour needle tip pass? 2. What is the area swept by the clock from 6 am to 6 pm? What is the area swept by the clock from 12 am to 6 pm?

Circle formula: l = 2 π R
In the formula, from 12:00 to 2:00, the minute needle tip passes 125.6cm; from 6:00 in the morning to 6:00 in the afternoon, the hour needle tip passes 50.24cm
Circle area formula: S = π R ^ 2
In the formula, from 6:00 a.m. to 6:00 p.m., the area swept by the hour hand is 200.96 square centimeters; from 12:00 a.m. to 6:00 p.m., the area swept by the hour hand is 100.48 square centimeters (this is the area from 12:00 a.m. to 6:00 p.m., if it is 6:00 a.m., add 200.96)

The sixth grade calculates the circumference and area of a circle
1.r=0.2 c= s= 2.r=2 c= s= 3.r=0.1 c= s= 4.r=0.3 c= s=
5.r=10 c= s= 6.r=20 c= s= 7.r=0.1 c= s= 8.r=1 c= s=
9.r=3 c= s= 10.r=0.02 c= s= 11.d=2 c= s= 12.d=0.4 c= s=
13.d=200 c= s= 14.d=0.2 c= s= 15.d=20 c= s= 16.d=0.6 c= s=
17.d=4 c= s= 18.d=40 c= s= 19.d=60 c= s= 20.d=400 c= s=
As soon as possible

1.r=0.2 c= 1.256 s= 0.1256 2.r=2 c=12.56 s=12.56 3.r=0.1 c=0.628 s=0.0314 4.r=0.3 c=1.884 s=0.2826
5.r=10 c=62.8 s=314 6.r=20 c=125.6 s=1256 7.r=0.1 c=0.628 s=0.0314 8.r=1 c=6.28 s=3.14
9.r=3 c=18.84 s=2826 10.r=0.02 c=0.1256 s=0.001256 11.d=2 c=6.28 s= 3.14 12.d=0.4 c=1.256 s=0.1256
13.d=200 c=628 s=31400 14.d=0.2 c=0.628 s=0.0314 15.d=20 c=62.8 s=314 16.d=0.6 c=1.884 s=0.2826
17. D = 4, C = 12.56, s = 12.56, 18. D = 40, C = 125.6, s = 1256, 19. D = 60, C = 188.4, s = 2826, 20. D = 400, C = 1256, s = 125600, give me extra points, OK? I'll play you numb

Calculate the perimeter and area of a circle with a radius equal to 10 cm (QBASIC)

Procedure:
CLS
A = 3.14 * 10 * 2
B = 3.14 * 10 ^ 2
Print "perimeter ="; a
Print "area ="; b
END