Solve the equation x × (x + 1) × (x + 2) × (x + 3) = 360,

Solve the equation x × (x + 1) × (x + 2) × (x + 3) = 360,


[x(x+3)][(x+1)(x+2)]=360
(x^2+3x)(x^2+3x+2)=360
Let t = x ^ 2 + 3x + 1, then (t-1) (T + 1) = 360, the solution is T ^ 2 = 361, T1 = 19, T2 = - 19
Then x ^ 2 + 3x + 1 = 19, the solution is X1 = 3, X2 = - 6
Or x ^ 2 + 3x + 1 = - 19, at this time (x + 3 / 2) ^ 2 + 71 / 4 = 0, contradiction, rounding
So X1 = 3, X2 = - 6

Elden Ring Premiere

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