If there are four positive integer solutions to the inequality 2x-3 ≤ m, then the range of M is______ ．

If there are four positive integer solutions to the inequality 2x-3 ≤ m, then the range of M is______ ．

2x-3 ≤ m, 2x ≤ m + 3, X ≤ m + 32, ∵ there are four positive integer solutions of this inequality, ∵ the positive integer solutions of the inequality are 1, 2, 3, 4, ∵ 4 ≤ m + 32 < 5, ∵ the value range of M is 5 ≤ m < 7. So the answer is: 5 ≤ m < 7

If the inequality 2x-a ≤ 0 has only two positive integer solutions, then the value range of a is?

2x≤a
Because x can only take 1 or 2
So the value of a is a number greater than or equal to 4 and less than 6
That's four or five

If inequality 2x-a

A is greater than or equal to 6 and less than 7

If the inequality 2x-1 > m (x ^ 2-1) satisfies - 2

If M is regarded as an unknown number and X as a parameter, it is actually a problem that the first-order equation is always less than 0
If a line is always less than 0 on [- 2,2], the value of two vertices is taken in, and the parameter range can be obtained
The solution of 2x-1 > 2 (x ^ 2-1) is: (1-radical 3) divided by 2