If point a (3x + 4,5-2x) is on the bisector of the second and fourth quadrants, find the coordinates of point a

If point a (3x + 4,5-2x) is on the bisector of the second and fourth quadrants, find the coordinates of point a

Because point a is on the bisector of the angle of the second and fourth quadrants, so: | 3x + 4 | = | 5-2x |, the solution is: x = 1 / 5, x = - 9
So a (23 / 5, - 23 / 5), (- 23,23)

If the point P (- 3, a) is on the bisector of the angle between the second and fourth quadrants, then a=
What is the meaning of the sentence "on the bisector of the angle between the second and fourth quadrants"

Because the point P (- 3, a) is on the bisector of the angle between the second and fourth quadrants, the distance between the point and the two sides of the angle, that is, the X and Y axes, is equal. But because the abscissa of point P is - 3, so point P is in the second quadrant, the ordinate a must be positive, so a = 3

In the plane rectangular coordinate system, an isosceles right triangle ABC is placed in the second quadrant, leaning on the two coordinate axes, and intersecting with the parabola y = AX2 + ax + B
B. Where a (0,2) B (- 3,1), the intersection of parabola and Y axis and D (0, - 2)
Find the coordinates of point C;
The analytic formula of parabola

① If ∠ ACB = 90 ° and BD ⊥ CO is made through B, the perpendicular foot is D, and D is on the negative half axis of X axis. From ⊿ AOC ≌ ⊿ CDB, BD = OC = 1, CD = OA = 2, so the coordinates of point B are (- 3,1). The coordinates of another vertex of isosceles right triangle with AC as right side can be obtained by the same method as (2,1) and (- 2,3), (1, - 1)