The intercept of the straight line passing through point P (1,2) on the positive half axis of X axis and the positive half axis of Y axis are a and B respectively, and the minimum value of AB is obtained It's better to have a process```

The intercept of the straight line passing through point P (1,2) on the positive half axis of X axis and the positive half axis of Y axis are a and B respectively, and the minimum value of AB is obtained It's better to have a process```

The analytic formula of the line passing through point P (1,2) and intersecting with the positive half axis of X axis and the positive half axis of Y axis is Y-2 = K (x-1), where k

If the intercept of the straight line passing through point P (1,2) on the positive half axis of X axis and Y axis is a and B respectively, then the minimum value of a + B is

A + B minimum = 3 + 2 √ 2
As shown in the picture
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Given that the line passes through (2,1), find the minimum value of the sum of the intercepts of the line L on the positive half axis of X axis and the positive half axis of Y axis, and find the equation of the line L at this time

Let the intercept on the x-axis be a and the intercept on the y-axis be B
Then: X / A + Y / b = 1
Substituting point (2,1), we get 2 / A + 1 / b = 1
Sum of intercept a + B = (a + b) (2 / A + 1 / b)
=2+a/b+2b/a+1
=3+a/b+2b/a
≧3+2√2
If and only if a / b = 2B / A, the equal sign holds
That is: B / a = √ 2 / 2
Then k = - B / a = - √ 2 / 2
Therefore, the minimum value of the sum of intercept is 3 + 2 √ 2, and the linear equation is: √ 2x + 2y-2 - √ 2 = 0

What is the intercept of the line - X / A ^ 2 + Y / b ^ 2 = 1 on the X axis?

x/(-a²)+y/b²=1
So the intercept on the x-axis is - A & # 178;

If the line segment Mn is parallel to the X axis, m {1,2}, and Mn = 4, then what is the coordinate of the N point?
Don't miscalculate if you are in a hurry for a kind-hearted person

Parallel to the X axis, so the ordinate of n is 2
The abscissa is 1-4 = - 3 or 1 + 4 = 5
So the coordinates of N are (- 3,2) or (5,2)

Given that the line segment Mn is parallel to the y-axis, the coordinates of point m are (- 1,3). If Mn = 4, then the coordinates of N are______ ．

The coordinate of point m is (- 1,3), and the abscissa of point n is - 1. Counting four unit lengths up from point m along the parallel line, we get n (- 1,7); counting four unit lengths down from point m along the parallel line, we get n (- 1, - 1). The coordinate of n is (- 1,7), (- 1, - 1)

Given that the line segment Mn is parallel to the x-axis, and the length of Mn is 5, if M (2, - 2), then the coordinates and process of point n

If M is shifted 5 units to the left or right
N (- 3, - 2) or (7, - 2)

Given the line segment Mn = 4, Mn ‖ Y axis, if the point m coordinate is (- 1,2), then the point n coordinate is -______ ．

By setting the point n (- 1, y), ∵ given the line Mn = 4, m coordinate is (- 1, 2), ∵ Y-2 = 4, or Y-2 = - 4, the solution is y = 6 or y = - 2, that is, the point n coordinate (- 1, - 2), (- 1, 6). So the answer is: (- 1, - 2), (- 1, 6)

Given the point m (a, a + 1) and point n (3, - 1), and the line segment Mn is parallel to the X axis, then the coordinate of point m is?

（-2,-1）
Parallel to the x-axis indicates the same ordinate

Given that the line segment Mn = 4, Mn is parallel to the y-axis, if the point m coordinate is [- 1,2], then the point n coordinate is
The answers given by the teacher are [- 1,6], [- 1, - 2], but I think they are all wrong

Draw a coordinate axis. Find the M coordinate [- 1,2]. Extend 4 units up and down. The teacher is absolutely right