The equation of a line perpendicular to the line 2x + Y-1 = 0 and with an intercept of - 2 on the x-axis is

The equation of a line perpendicular to the line 2x + Y-1 = 0 and with an intercept of - 2 on the x-axis is

Because the two lines are perpendicular, the slope of the two lines is multiplied by - 1
So the slope of the line is 0.5
Let the line be y = 0.5x + B
Because the intercept on the x-axis is - 2, it must pass the point (- 2,0)
Substitute this point into y = 0.5x + B
The analytic formula is y = 0.5x + 1

According to Arrhenius formula, with the increase of temperature, the rate constant K will be (6), and the greater the activation energy, the rate constant K will be (7)
According to Arrhenius formula, with the increase of temperature, the rate constant K will be (6); for different reactions, the greater the activation energy, the rate constant K will be (7)

6 is increasing, 7 is increasing
The Arrhenius formula is written as k = AE EA / RT. K is the rate constant, R is the molar gas constant, t is the thermodynamic temperature, EA is the apparent activation energy, and a is the pre exponential factor (also known as the frequency factor)
With the increase of temperature, t increases, EA / RT decreases and K increases

At a certain temperature, the more negative the standard free energy of the chemical reaction, the more the standard equilibrium constant of the reaction (), the smaller the activation energy, the more the rate constant of the reaction（
The smaller the activation energy is, in this question, the condition given separately or derived from the negative change of the standard free energy? (that is, if the smaller is also changed to be empty, can you fill in the answer). By the way, let's talk about the answer, which is not given in the book

The more negative the standard free energy of chemical reaction becomes, the more (larger) the standard equilibrium constant of reaction is, and the smaller the activation energy is, the more (larger) the rate constant of reaction is
G=-RTLnK
So the more negative G is, the larger rtlnk is, and R and T are fixed values, so the larger K is
K = AE (- EA / RT) power, so the smaller the activation energy is, the greater the K is

At the same temperature, the reaction rate constant increases more times than that at the same temperature. Is it the reaction with higher activation energy or the reaction with lower activation energy?

Reaction with higher activation energy

Given that M is on the hyperbola y = 1 / 2x, point n is on the straight line y = x + 3, two points of Mn are symmetric about the y-axis, let the coordinates of point m be (a, b), then what are the vertex coordinates of y = - ABX * + (a + b) x?

Solution: because the coordinates of M are (a, b), and M is on the hyperbola y = 1 / 2x
So m (a, 1 / 2a) B = 1 / 2A
Because the two points of Mn are symmetric about the Y axis
So n (- A, 1 / 2a)
Because point n is on the line y = x + 3,
So 1 / 2A = - A + 3
So a = 2
So B = 1
So y = - ABX * + (a + b) x = - 2 (x-3 / 4) ^ 2 + 9 / 8
So the vertex coordinates are (3 / 4,9 / 8)
complete