Linear equation with intercept of 2 on x-axis and - 3 on y-axis

Linear equation with intercept of 2 on x-axis and - 3 on y-axis

What is the equation of a line passing through point a (- 1,4) with intercept 3 on the x-axis?
Such as the title

The equation of the straight line is: y = KX + B. from the problem, the point (- 1,4) (3,0) or (- 1,4) (- 3,0) on the straight line has 4 = - K + B, 1 0 = 3K + B, 2 or 4 = - K + B, 1 0 = - 3K + B, 2 is replaced by - 4 = 4K or - 4 = - 2K, k = - 1 or K = 2

What is the equation of equal intercept on x-axis and y-axis after passing through (- 2, - 3)?

(1) When the intercept is 0, let the equation be y = KX
The coordinates are substituted into - 3 = - 2K, k = 3 / 2
That is, the equation is y = 3 / 2 X
(2) When the intercept is not 0, let the equation be x / M + Y / M = 1
-2/m+(-3)/m=1
M = - 5
That is, the equation is x + y + 5 = 0

It is known that the intercept of line L on x-axis is 1 larger than that on y-axis, and it passes through a certain point P (6, - 2)

Column intercept equation: X / (a + 1) + Y / a = 1, where a is the intercept on the Y axis
Substituting (6, - 2) into
6/(a+1)-2/a=1
6a-2(a+1)=a(a+1)
a²+a=6a-2a-2
a²-3a+2=0
(a-2)(a-1)=0
A = 1 or 2
Then the straight line is x / 2 + y = 1, that is, x + 2y-2 = 0 or X / 3 + Y / 2 = 1, that is, 2x + 3y-6 = 0